# 2. Suppose you pass light from a He-Ne laser through two slits separated by 0.0100 mm andfind that the third bright line on a screen is formed at an angle of 10.95° relative to the incidentbeam. What is the wavelength of the light? OPTICSWave optics. Interference. Diffraction. Polarization1. Young's Double Slit ExperimentConstructive interference:Sereen6 = kA = 2kDestructive interference:8 = (2k + 1);Coordinates of bright and dark fringes on the screen:IA(*+): av=-k: VanimMmax =+Here 8 is path difference (m), a is wavelength of light (m), / is distance from the slits to the screen(m), k = 0, 1, 2, 3 ... is minimum or maximum order number, d is distance between the slits (m),Ymax are coordinates of bright fringes on the screen (m), ymin are coordinates of dark fringes onthe screen (m), Ay is width of the fridges (m).2. Interference in thin films:AirConstructive interference:21Vn? – sin? a =-= (2k +1)вDestructive interference:Air21Vn2 – sin² a = kAHere n is refractive index of the film, a is angle of light incidence, k= 0, 1, 2, 3 ... is minimum ormaximum order number, å is wavelength of light (m), / is thickness of the film (m).3. Single-Slit DiffractionConstructive:a sine = +(2k + 1)5Destructive:a sine = tkda is the slit width, k = 0, 1, 2, 3 ... is minimum or maximum ordernumber, À is wavelength of light (m), e is the angle oncorresponding minimum or maximum.4. Diffraction grating:d sin g = ±kAd = /N is period of diffraction grating and N is number of lines per unit length, o is angle oncorresponding minimum or maximum, k = 0, 1, 2... is minimum or maximum order number, å iswavelength of light (m).5. Resolution of the optical instrumentsLimiting angle of resolution emin:1.222e,minMinimum separation distance d:d = L0minA is wavelength of light (m), D is aperturediameter, for human eye pupil diameter (m).

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Step 1

According to the interference phenomenon, the wavelength of the light is,

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