Interference patterns do not have an infinite number of lines, since there is a limit to how big diffraction order can be. Calculate the highest-order constructive interference possible in a double slit experiment under the following conditions: the wavelength of a source is 528 nm and distance between the slits is 0.010 mm.

You perform a double‑slit experiment in order to measure the wavelength of the new laser that you received for your birthday. You set your slit spacing at 1.09 mm and place your screen 8.39 m from the slits. Then, you illuminate the slits with your new toy and find on the screen that the tenth bright fringe is 4.57 cm away from the central bright fringe (counted as the zeroth bright fringe). What is your laser's wavelength ? expressed in nanometers?

Question: In a double-slit experiment, the wavelength of the light source is 520 nm, the slit separation is 35 um, and the slit width is 7 um. Find: What is sin(theta) of the first minimum diffraction envelope? How many bright interference fringes are within the central peak of the diffraction envelope? The value of alpha for the second bright fringe in the first minimum diffraction envelope is ? *pi. The value of beta for the second bright fringe in the first minimum diffraction envelope is ? *pi. What is the ratio of the intensity of the second bright fringe to the intensity of the central fringe?

The phenomenon of diffraction occurs due to the tendency of waves to spread when they encounter an opening or obstacle. Single-slit diffraction is a phenomenon observed when a wave passes through a narrow opening, such as a slit, and spreads out after passing through it. The degree of diffraction depends on the dimensions of the aperture in relation to the wavelength of the incident wave. Statement: A slit of width a is illuminated with white light. For what value of slit width will we have the first minimum for blue light, with ? = 450 ??, appearing at ? = 25th? Question options: a) 1.50 µm b) 1.98µm c) 1.05µm d) 3.60 µm e) 0.37µm