I need an answer to this. Can you help me? 2. Which among the choices satisfy the given differential equations. Answer/s should be letter orletters only.2а. у"- Зу'— 10у -D0-5хA. y= C,eB. y = C,e 5x + C.e 2x+ C,e2*В. у %3 С,еC. y = C,e* + C,e²*D. y = C,e* + C,e 2*-5х

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Answered: 2. Which among the choices satisfy the…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Match column B with the correct answer on column A, write only the capital letter of the answer on the blank provided at the left side/right side of the test paper. Match from column A the solution of the differential equations on column B. Column A A. xlnx + ylny = c B. 2y = x4 + cx2 C. e(x^2) + y2 = c D. x2 = cy3 E. x2 y = 2x4 + c F. ylnx + xlny = c G. x2 (x2 + 2y2) = c H. x (y + x2) = c (y – 2x) I. xy2 – x2y + 3x2 – 2y = c J. xy3 = 2y2 + 4y + 4 + cey K. y (x2 + c) + 2 = 0 L. (y – x) (y + 3x)3 = cx3 M. x2 y = 2x2 + c N. x (y + 1) = (1 + cx) ey O. e(-x^2) + y-2 = c P. (y + x2) = c (y – 2x) Q. x2y2 + 2xy – x2 = c R. x4 = c2 (4x2 + y2) S. x2 (x+ 2y) = c T. x2 + y2 – 3xy = c Column B (x – y) (4x + y) dx + x (5x – y) dx = 0 xy3 dx + e(x^2) dy = 0 y dx + (3x – xy + 2) dy = 0 2 (2x2 + y2) dx – xy dy = 0 (x2 + y2) – xy dy = 0 (2x – 3y) dx + (2x – 3x) dy = 0 x2 yy’ = ey (x4 + 2y) dx – x dy = 0 (3x2 – 2xy + 3y2) dx = 4xydy
Match column B with the correct answer on column A, write only the capital letter of the answer on the blank provided at the left side/right side of the test paper. Match from column A the solution of the differential equations on column B. Column A A. xlnx + ylny = c B. 2y = x4 + cx2 C. e(x^2) + y2 = c D. x2 = cy3 E. x2 y = 2x4 + c F. ylnx + xlny = c G. x2 (x2 + 2y2) = c H. x (y + x2) = c (y – 2x) I. xy2 – x2y + 3x2 – 2y = c J. xy3 = 2y2 + 4y + 4 + cey K. y (x2 + c) + 2 = 0 L. (y – x) (y + 3x)3 = cx3 M. x2 y = 2x2 + c N. x (y + 1) = (1 + cx) ey O. e(-x^2) + y-2 = c P. (y + x2) = c (y – 2x) Q. x2y2 + 2xy – x2 = c R. x4 = c2 (4x2 + y2) S. x2 (x+ 2y) = c T. x2 + y2 – 3xy = c Column B (x – y) (4x + y) dx + x (5x – y) dx = 0 xy3 dx + e(x^2) dy = 0 y dx + (3x – xy + 2) dy = 0 2 (2x2 + y2) dx – xy dy = 0 (x2 + y2) – xy dy = 0 (2x – 3y) dx + (2x – 3x) dy = 0 x2 yy’ = ey (x4 + 2y) dx – x dy = 0 (3x2 – 2xy + 3y2) dx = 4xydy (1 + lnx) dx + (1 + lny) dy = 0
Match column B with the correct answer on column A, write only the capital letter of the answer on the blank provided at the left side/right side of the test paper. Match from column A the solution of the differential equations on column B. Column A A. xlnx + ylny = c B. 2y = x4 + cx2 C. e(x^2) + y2 = c D. x2 = cy3 E. x2 y = 2x4 + c F. ylnx + xlny = c G. x2 (x2 + 2y2) = c H. x (y + x2) = c (y – 2x) I. xy2 – x2y + 3x2 – 2y = c J. xy3 = 2y2 + 4y + 4 + cey K. y (x2 + c) + 2 = 0 L. (y – x) (y + 3x)3 = cx3 M. x2 y = 2x2 + c N. x (y + 1) = (1 + cx) ey O. e(-x^2) + y-2 = c P. (y + x2) = c (y – 2x) Q. x2y2 + 2xy – x2 = c R. x4 = c2 (4x2 + y2) S. x2 (x+ 2y) = c T. x2 + y2 – 3xy = c Column B 2y dx = 3x dy (y2 – 2xy + 6x) dx – (x2 – 2xy + 2) dy = 0 2(y – 4x2) dx + xdy = 0 y' = xy2 (xy2 + y – x) dx + x (xy + 1) dy = 0 (x – y) (4x + y) dx + x (5x – y) dx = 0 xy3 dx + e(x^2) dy = 0 y dx + (3x – xy + 2) dy = 0 2 (2x2 + y2) dx – xy dy = 0 (x2 + y2) – xy dy = 0 (2x – 3y) dx + (2x – 3x) dy = 0 x2 yy’ =…
A population growing with harvesting will behave according to the differential equationdydt=0.1y(1−y1300)−cdydt=0.1y(1-y1300)-cy(0)=y0y(0)=y0Find the value for c for which there will be only one equilibrium solution to the differential equationc = 32.5Correct If c is less than the value found above, there will be Correct equilibria. If c is greater than the value found above, there will be Incorrect equilibria.
A population growing with harvesting will behave according to the differential equationdydt=0.1y(1−y1300)−cdydt=0.1y(1-y1300)-cy(0)=y0y(0)=y0Find the value for c for which there will be only one equilibrium solution to the differential equationc = If c is less than the value found above, there will be equilibria. If c is greater than the value found above, there will be equilibria.
Find a general solution for y'+ (1/x)y = 0, for x > 0. To receive any credit, you must use the technique for solving linear differential equations.
solve the for the general solution of the differential equation( linear homologous equation):(4D4 - 4D3 - 23D2 + 12D +36 )y =0
Determine the solution of the differential equation: y' + 5y = 0.. Single choice.
Answer in complete solution in this Differential Equations: (16D7 – 32D6 – 40D5 + 72D4 + 37D3 – 40D2 – 7D+ 6)y = 0
Find the general solution of the differential equation or state that the differential equation is not separable. ( Enter NOT SEPARABLE if the equation is not separable.) y' = x6y
A tank with a capacity of 250 gal is intended to be used to prepare a sugar solution. The tank initially contains 100 gal of fresh water, in which 25 lb of sugar is dissolved. On the other hand, a sugar solution enters the tank at a rate of 5 gal/min, which contains 3 lb/gal, while the mixed solution leaves at a rate of 2 gal/min.(a) Write the differential equation and the conditions that allow to determine the amount of sugar in the tank depending on the time.(b) Determine the amount of sugar in the tank at any time t.(c) How long will it take for the tank to contain 160 lb of sugar?
For the two armies X and Y, the X army is about to attack Y army which has only 7725 troops while the X army has 12440 troops. The Y army however superior military equipment’s which make each Y soldier 1.5 times as effective as X soldier. Develop a mathematical model using differential equations and explain for i) which army will win ii) Estimate how many troops of the winning army will be left at the end. iii) How long the battle will end. The kill rates of X and Y are 0.5 and 0.75 respectively.

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2. Which among the choices satisfy the given differential equations. Answerls should be letter or letters only. 2а. у" — Зу'- 10y %3D0 + C,e?x B. y = C,e 3* + C,e 2* C. y = C,e* + C,e²* D. y = C,e5* +C,e * -5x A. y= C,e 3x -5x -2х