2.50 kg particle that is moving horizontally over a floor with velocity (-3.00 m/s)ˆj undergoes a completely inelastic collision with a 4.00 kg particle that is moving horizontally over the floor with velocity (4.50 m/s)iˆ. The collision occurs at xy coordinates (-0.500 m, -0.100 m). After the collision and in unit-vector notation, what is the angular momentum of the stuck-together particles with respect to the origin?
2.50 kg particle that is moving horizontally over a floor with velocity (-3.00 m/s)ˆj undergoes a completely inelastic collision with a 4.00 kg particle that is moving horizontally over the floor with velocity (4.50 m/s)iˆ. The collision occurs at xy coordinates (-0.500 m, -0.100 m). After the collision and in unit-vector notation, what is the angular momentum of the stuck-together particles with respect to the origin?
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter13: Rotation Ii: A Conservation Approach
Section: Chapter Questions
Problem 48PQ: Two particles of mass m1 = 2.00 kgand m2 = 5.00 kg are joined by a uniform massless rod of length =...
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2.50 kg particle that is moving horizontally over a floor
with velocity (-3.00 m/s)ˆj undergoes a completely inelastic collision
with a 4.00 kg particle that is moving horizontally over the
floor with velocity (4.50 m/s)iˆ. The collision occurs at xy coordinates
(-0.500 m, -0.100 m). After the collision and in unit-vector
notation, what is the
with respect to the origin?
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