Hinge e= 0.50m Bullet =10g 400 ms ulet d= 1.00mM-15kg

University Physics Volume 3
17th Edition
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:William Moebs, Jeff Sanny
Chapter4: Diffraction
Section: Chapter Questions
Problem 78P: The first-order Bragg angle for a certain crystal is 12.1°. What is the second-order angle?
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A door 1.00m wide of mass 15.0 kg, is hinged at one side so that it can rotate without friction about a vertical axis. It is unlatched. A police officer fires a bullet with a mass of 10.0g and a speed of 400m/s into the exact center of the door in a direction perpendicular to the door.
(use: the moment of inertia of the rotating door at the hinge, Idoor =1/3Md2)

a. What is the initial momentum of the system?
b. What is the angular speed of the door just after the bullet embeds itself in the door?

Hinge
l= 0.50m
m =10g
Bullet
Vbulet = 100 m/s
d= 1.00mM-15 kg
Before
After
Transcribed Image Text:Hinge l= 0.50m m =10g Bullet Vbulet = 100 m/s d= 1.00mM-15 kg Before After
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