Question 1"A three particle system with with masses: m1 = 2.0 Kg, m2 = 4.0 Kg and m3 = 8.0 Kg. The position co-ordinates for particle 1 are (3,3), for particle 2 are (2,1) and for particle 3 are (1,2). What will be the x coordinate of the system s center of mass?"o 1.571.282.22The data is not enough to calculate the center of mass

Given: m1= 2.0 kg , coordinate 3,3m2=4.0 kg, coordinate 2,1m3=8.0 kg, coordinate 1,2 Find:- What…

Answered: A three particle system with with…

A three particle system with with masses: m1 = 2.0 Kg, m2 = 4.0 Kg and m3 = 8.0 Kg. The position co-ordinates for pa 1.57 1.28 2.22 The data is not enough to calculate the center of mass

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

PART 1: A 5.00 kg particle has the xy coordinates (1.20 m, 2.00 m), and a 6.00 kg particle has the xy coordi-nates (0.300 m, 0.750 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you placea 4.00 kg particle such that the center of mass of the three-particle system has the coordinates (0.500 m, 0.900 m)? PART 2: A rope is used to pull a 3.5 kg block at constant speed 6 m along a horizontal oor. The force onthe block from the rope is 7 N and directed = 20 above the horizontal. What are (a) the work done by therope's force, (b) the increase in thermal energy of the block- oor system. PART 3: Draw a labelled gure to explain the idea of turning point in terms of energy.
three particle system with with masses: m1 = 2.0 Kg, m2 = 4.0 Kg and m3 = 8.0 Kg. The position co-ordinates for particle 1 are (3,3), for particle 2 are (2,1) and for particle 3 are (1,2). What will be the y coordinate of the system s center of mass?
How fast can you set the Earth moving? In particular, when you jump straight up as high as you can, you give the Earth a maximum recoil speed of what order of magnitude? Model the Earth as a perfectly solid object. In your solution, state your assumptions, i.e. what data your take as given and what you derive.
Block 1 of mass m1 slides along a frictionless floor and into a one-dimensional elastic collision with stationary block 2 of mass m2 = 3m1. Prior to the collision, the center of mass of the twoblock system had a speed of 3.00 m/s. Afterward, what are the speeds of (a) the center of mass and (b) block 2?
Three people of roughly equal masses on a lightweight banana boat sit along the x axis at positions xA = 1.0 m, xB = 5.0 m, and xc = 6.0 m, measured from the left-hand end. Find the position of the cm. Ignore the boat’s mass.
One astronaut is 75kg, and another who is 3.4 m away in the x-direction is 85kg. How far from the first astronaut is their mutual center of mass? Do not actually solve the problem numerically or algebraically, just pick the one equation and define the relevant knowns and single unknown.
Three masses at m1 = 1 kg, r1 = 1i + 2j m2 = 2 kg, r2 = -2i +3j m3 = 3 kg, r3 = 0i + 3j. The system's center of mass is at rcm = xi + yj. Find both x and y.
A man with mass m1 = 51 kg stands at the left end of a uniform boat with mass m2 = 168 kg and a length L = 3.3 m. Let the origin of our coordinate system be the man’s original location as shown in the drawing. Assume there is no friction or drag between the boat and water. 1) If the man now walks to the right edge of the boat, what is the location of the center of mass of the system? 2) After walking to the right edge of the boat, how far has the man moved from his original location? (What is his new location?) 3) After the man walks to the right edge of the boat, what is the new location the center of the boat? 4) Now the man walks to the very center of the boat. At what location does the man end up?
The vector position of a 3.50-g particle moving in the xy plane varies in time according to r rightarrow = (3i^ + 3j^ )t + 2j^ t2,where t is in seconds and r rightarrow is in centimeters. At the same time, the vector position of a 5.50-g particle varies asr2 rightarrow = 3i^ - 2i^t2 - 6j^ t. At t = 2.50 s, determine (a) the vector position of the center of mass, (b) the linear momentum of the system, (c) the velocity of the center of mass,(d) the acceleration of the center of mass, and (e) the net force exerted on the two-particle system.
Two particles P andQare released from rest 1.0 m apart.P has a mass of 0.10 kg, and Qa mass of 0.30 kg.P andQattract each other with a constant force of 1.0 * 10-2 N. No external forces act on the system. (a) What is the speed of the center of mass of P and Q when the separation is 0.50 m? (b) At what distance from P’s original position do the particles collide?
1.A fireworks rocket is launched vertically into the night sky with an initial speed of 44.2 m/s. The rocket coasts afterbeing launched, then explodes and breaks into two pieces of equal mass 2.50 s later. (a) If each piece follows a trajectory that is initially at 45.0° to the vertical, what was their speed immediately after the explosion? (b) What is the velocity of the rocket’s center of mass before and after the explosion? (c) What is the acceleration of the rocket’s center of mass before and after the explosion?Explain and labled the drawing.
3 a) Find the center of mass of uniform meter Rod. b) A 450?? bullet moving at 672 ?/? strikes a 715?? wooden block at rest on a frictionless surface. The bullet emerges with its speed reduced to 420 m/s. Find resulting speed of block?