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20.0° has a spring of force constant k = 480 N/m fastened securely at the bottom so that the spring is parallel to the surface as shown in the figure below. A block of mass m 2.29 kg is placed on the plane at a distance d = 0.297 m fromAn inclined plane of angle ethe spring. From this position, the block is projected downward toward the spring with speed v0.750 m/s. By what distance is the spring compressed when the block momentarily comes to rest?

Question
20.0° has a spring of force constant k = 480 N/m fastened securely at the bottom so that the spring is parallel to the surface as shown in the figure below. A block of mass m 2.29 kg is placed on the plane at a distance d = 0.297 m from
An inclined plane of angle e
the spring. From this position, the block is projected downward toward the spring with speed v
0.750 m/s. By what distance is the spring compressed when the block momentarily comes to rest?
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20.0° has a spring of force constant k = 480 N/m fastened securely at the bottom so that the spring is parallel to the surface as shown in the figure below. A block of mass m 2.29 kg is placed on the plane at a distance d = 0.297 m from An inclined plane of angle e the spring. From this position, the block is projected downward toward the spring with speed v 0.750 m/s. By what distance is the spring compressed when the block momentarily comes to rest?

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Step 1

Let m be the mass of the block, d be the distance between the uncompressed spring and block, v be the velocity of the block, l be the length of the uncompressed spring, x be the distance by which the spring is compressed, k be the spring constant.

Write the given numerical values.

m 2.29 kg
v 0.75 m/s
d 0.297 m
k 480 N/m
0-20°
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m 2.29 kg v 0.75 m/s d 0.297 m k 480 N/m 0-20°

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Step 2

Refer the following diagram to analyse the motion of the block and compression of spring.

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Step 3

Write the expression for initial kinetic and potential energy of the system. As t...

1
K.E
2
P.E, mg (d)sin
sin0
+ /
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1 K.E 2 P.E, mg (d)sin sin0 + /

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