small body of mass m resting on a smooth horizontal plane is attached by threads to a point P (see figure) and, by means of a weightless pulley, to a hanging weight possessing the same mass m. Besides, the small body is also attached to the ceiling by means of a light non-deformed vertical spring of length L0 = 50 cm and spring constant k = 5mg/L0. The thread connecting the small body and point P having been burned, the small body starts moving. Find its velocity at the moment when it is breaking off the plane.

Q: I find a spring that is labeled "80 N/m", but it is actually 3.5 inches long. I fasten a beam…

A: The length of the spring is given to be 3.5 inches. And it has been fastened from a beam 789mm above…

Q: A 20 kg mass is fastened to a spring of force constant k= 250 N/m by a string passing over a light…

A: Given: The mass of object is m=20 kg. The spring constant is k=250 N/m. The amplitude is A=0.4 m.…

Q: A particle of mass m is projected from point A with an initial velocity v0 perpendicular to line OA…

A: Use principle of conservation of angular momentum

Q: an air-track glider of mass 0.100 kg is attached to the end of a horizontal air track by a spring…

A:

Q: A block of mass ? = 300 g is released from rest from the top of a frictionless ramp. At the bottom…

A: Given Data : The mass of the block is given as m = 300 g. The spring constant of the spring is given…

Q: A simple pendulum, 2.0 m in length, is released by a push when the support string is at an angle of…

A:

Q: A 1.78 kg ball rolls on a frictionless horizontal surface at 5.17 m/s and collides with a stationary…

A:

Q: A scene in a movie has a stuntman falling through a floor onto a bed in the room below. The plan is…

A: Potential energy possessed by the mass at the given height is converted into the spring potential…

Q: A block of mass m = 0.32 kg is set against a spring with a spring constant of k1 = 681 N/m which has…

A: Using the conservation of energy, 12k1d12-μkmgx=12k2d22

Q: A 69.5 kg bungee jumper is standing on a tall platform (h0 = 53 m), as seen in the photo. The bungee…

A:

Q: A 3.31-kg box placed against a horizontal spring with a force constant of k = 236 N/m compresses the…

A:

Q: A 1.63 kg ball rolls on a frictionless horizontal surface at 5.5 m/s and collides with a stationary…

A: Mass of the ball m1=1.63 kg, velocity of the ball before collision u=5.5 m/s, velocity of ball after…

Q: The figure shows a track made up of two sections and located in a vertical plane. Section ab is…

A:

Q: A spring having a spring constant of 500.0 N/m is permanently attached to a 4.00kg mass initially at…

A:

Q: 1.2 kg A spring of spring constant k is hung from a horizontal support. A block of mass m = 1.2 kg…

A: Given quantities: mass of the block (m) = 1.2 kg acceleration due to gravity (g) = 10 m/s2…

Q: A weight of mass m is at rest at O when suspended from a spring, as shown. When it is pulled down…

A: The rate of change of gravitational potential energy is  smallest at A, therefore statements 1, 2…

Q: To what height above its lowest point does the mass swing on the other side?

A:

Q: A simple pendulum is formed of a bob of mass m attached to a string of ler The bob is displaced from…

A: At mean position particle will have maximum velocity that is Aw. (w = omega=angular velocity)

Q: Consider a block of mass 0.270 kg attached to a spring of spring constant 160 N/m. The block is…

A:

Q: 50 N/m |0.5 kg X = -0.3 m X = 0m X = 0.3 m A block of mass 0.5 kg on a horizontal surface is…

A: We will use Hooke's Law for this :-                  F = -k x   Negative sign denotes that the force…

Q: k m A block of mass m = 5.20 kg is being suspended at rest by an extended spring of spring constant…

A: M = 5.2kg  K= 36 N/m  F= 20N  s= 2.45m

Q: A light spring with spring constant 1100 N/m hangs from an elevated support. From its lower end…

A:

Q: Consider a pendulum of mass “m" attached to a spring of mass "M" that is free to move in single…

A:

Q: A particle with mass 0.5 kg is moving in x-y plane. Its velocity is described as a function of time…

A: Given, the velocity(v) vector as a function of time, we have, v→ = (3i^ - 4tj^) m/s

Q: 47. An inclined plane of angle 20.0° has a spring of 500 N/m fastened securely at the bottom so that…

A:

Q: A 1.5 kg object falls from a height of 2.0 m onto a spring scale with a spring constant of 1.5x10 5…

A: Use conservation of energy. This gives: mgh = (1/2)kx2 Here, m is the mass g is the acceleration due…

Q: A block of mass 2.0 kg is attached to a horizontal spring that has a force constant of 100.0 N/m .…

A:

Q: Consider an object of mass 0.150kg that is attached to a horizontal spring of spring constant 35.2…

A:

Q: The force required to compress a non-standard spring as a function of displacement from equilibrium…

A:

Q: ( ANSWER e,f, and g ), a is given ) You have two equal masses m1 and m2 and a spring with a…

A: Given: The mass m1 = m2 = 0.500 kg. The spring constant k = 290 N/m. You now pull the mass m2 down a…

Q: A block of mass m2 = 10.0 kg, at rest on a horizontal surface that has negligible friction, is…

A: using conservation of momentum mu + MV = (m +M) v 14(3.2) + 10(0) = (14+10)v v = 1.87 m/s (combined…

Q: I just need the last part of the question

A: According to work energy theorem, change in kinetic energy is equal to work done by spring and…

Q: tion between the block and the plane is μk = 0.13. In the initial position, where the spring is…

A:

Q: A simple pendulum is suspended from the ceiling by means of a string and has a length of 1.56 m…

A: Given Data:- Length of the pendulum is l=1.56 m Initial speed of the pendulum is v0=1.73 m/s…

Q: A bob of mass m, attached to a string of length L = 1.8 m, has a speed v = 1 m/s at the equilibrium…

A: Given:-  The mass of the bob is m. The length of the string is L = 1.8 m.  The speed of the bob in…

Q: A brick of mass m = 0.48 kg is set against a spring with a spring constant of k1 = 619 N/m which has…

A: Given: m =0.48 kgk1=619 N/md1=0.1mk2=244 N/mμk=0.5x=1md2=?

Q: Examine the situation below. Using the information provided, determine... a. The speed at point A.…

A: We need to apply the law of conservation of energy to solve the given problem.

Q: A spring with a spring constant of k = 192 N/m is initially compressed by a block a distance d =…

A:

Q: The block of mass m 1.60 kg slides along the horizontal rough plane as shown in the figure. The…

A: We solve this problem using conservation of energy

Q: The system shown in the figure is in equilibrium. Masses mj& m2 are 2 kg and 8 kg respectively.…

A: Draw the free-body diagram of the 2 kg mass.

Q: A horizontal spring with stiffness 0.4 N/m has a relaxed length of 16 cm (0.16 m). A mass of 18…

A:

Q: A cube of a mass m=0.37 kg is set against a spring with a spring constant of k1=656 N/m which has…

A: Given,mass of the cube, m = 0.37 kgspring constant, K1 = 656 N/mspring constant, K2 = 181 N/mspring…

Q: A 1.71 kg ball rolls on a frictionless horizontal surface at 5.17 m/s and collides with a stationary…

A: Calculate the velocity of block after impact by using conservation of linear momentum.…

Q: A bullet with mass 4.95 g is fired horizontally into a 1.972-kg block attached to a horizontal…

A: Given information: The mass of the bullet (m1) = 4.95 g = 0.00495 kg The mass of the block (m2) =…

Q: A 0.10 kg mass vibrates in the x-direction without friction at the end of a massless horizontal…

A: mass (m) = 0.10 kg Spring constant (k) = 10 NmMaximum displacement from equilibrium position (A) =…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.