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20(g), Rp = 4.3 X 1O For a general reaction: A(g) + 3B( equilibrium mixture of the three gases at 300°C, the partial pressure of B is 0.65 b: at 300K.

20(g), Rp = 4.3 X 1O For a general reaction: A(g) + 3B( equilibrium mixture of the three gases at 300°C, the partial pressure of B is 0.65 b: at 300K.

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 76AP: Methanol can be synthesized by means of the equilibriumreaction CO(g)+2H2(g)CH3OH(g) for which the...
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*both temps in k

Calculate the partial pressure of C in the equilibrium mixture in units of bar 
Explain if the reactants or products are favoured at equilibrium

For a general reaction: A(g) + 3B(g) = 2C(g), Kp= 4.3 × 10¬³ at 300K. In an equilibrium mixture of the three gases at 300°C, the partial pressure of B is 0.65 bar and that of A is 0.28 bar.
Transcribed Image Text:For a general reaction: A(g) + 3B(g) = 2C(g), Kp= 4.3 × 10¬³ at 300K. In an equilibrium mixture of the three gases at 300°C, the partial pressure of B is 0.65 bar and that of A is 0.28 bar.
For a general reaction: A(g) + 3B(g) = 2C(g), Kp= 4.3 × 10¬³ at 300K. In an equilibrium mixture of the three gases at 300°C, the partial pressure of B is 0.65 bar and that of A is 0.28 bar.
Transcribed Image Text:For a general reaction: A(g) + 3B(g) = 2C(g), Kp= 4.3 × 10¬³ at 300K. In an equilibrium mixture of the three gases at 300°C, the partial pressure of B is 0.65 bar and that of A is 0.28 bar.
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