24) Use the Contingency Table created for the variables eye and travel to find the probabilitiesbelow (when identified use probability rule to find probability). The events are defined asfollows: A={brown eyes} and B{drive to school}а. Р(А)b. Р(В)c. Complement rule: P(Ad. Complement rule: P(Be. P(Aand B)f. Addition rule: P(Aor B)g. Conditional Probability rule: P(AB)h. Conditional Probability rule: P(B|A) Contingency table results:Rows: EyeColumns: TravelBikeOtherWalkTotalBusDrive55Blue34912387Brown17085Gray001103034Green12.1Hazel30352Other01Total441831312216Lс

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Asked Oct 17, 2019
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Need answers e though h. 

24) Use the Contingency Table created for the variables eye and travel to find the probabilities
below (when identified use probability rule to find probability). The events are defined as
follows: A={brown eyes} and B{drive to school}
а. Р(А)
b. Р(В)
c. Complement rule: P(A
d. Complement rule: P(B
e. P(Aand B)
f. Addition rule: P(Aor B)
g. Conditional Probability rule: P(AB)
h. Conditional Probability rule: P(B|A)
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24) Use the Contingency Table created for the variables eye and travel to find the probabilities below (when identified use probability rule to find probability). The events are defined as follows: A={brown eyes} and B{drive to school} а. Р(А) b. Р(В) c. Complement rule: P(A d. Complement rule: P(B e. P(Aand B) f. Addition rule: P(Aor B) g. Conditional Probability rule: P(AB) h. Conditional Probability rule: P(B|A)

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Contingency table results:
Rows: Eye
Columns: Travel
Bike
Other
Walk
Total
Bus
Drive
55
Blue
3
49
1
2
3
87
Brown
1
70
8
5
Gray
0
0
1
1
0
30
34
Green
1
2.
1
Hazel
30
35
2
Other
0
1
Total
4
4
183
13
12
216
Lс
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Contingency table results: Rows: Eye Columns: Travel Bike Other Walk Total Bus Drive 55 Blue 3 49 1 2 3 87 Brown 1 70 8 5 Gray 0 0 1 1 0 30 34 Green 1 2. 1 Hazel 30 35 2 Other 0 1 Total 4 4 183 13 12 216 Lс

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Expert Answer

Step 1

Given data is:

 

 

Travel

 

 

 

Bike

Bus

Drive

Other

Walk

Total

Eye

Blue

0

3

49

1

2

55

Brown

3

1

70

8

5

87

Gray

0

0

1

0

0

1

Green

1

0

30

2

1

34

Hazel

0

0

30

2

3

35

Other

0

0

3

0

1

4

 

Total

4

4

183

13

12

216

 

Let A is brown eyes and B is drive to school.

a.

See the above given table,

Total number of brown eyes or in the other world says favorable outcome = 87

Total outcome = 216

Now, the probability P(A) is calculated as follows:

Favorable Outcome
P(A)
Total Outcome
87
216
-0.4028
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Favorable Outcome P(A) Total Outcome 87 216 -0.4028

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Step 2

b.

See the above given table,

Total number of drive to school or in the other world says favorable outcome = 183

Total outcome = 216

Now, the probability P(B) is calculated as follows:

Favorable Outcome
P(B)
Total Outcome
183
216
0.8472
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Favorable Outcome P(B) Total Outcome 183 216 0.8472

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Step 3
Complement rule is:
P(A)1-P(A)
Now, P(A) will be calculated as follows:
P(A)1-P(A)
=1-0.4028
0.5972
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Complement rule is: P(A)1-P(A) Now, P(A) will be calculated as follows: P(A)1-P(A) =1-0.4028 0.5972

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