25 <> After 46.0 min, 24.0% of a compound has decomposed. What is the half-life of this reaction assuming first-order kinetics? min t1/2 =

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.49QE: When formic acid is heated, it decomposes to hydrogen and carbon dioxide in a first-order decay....
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After 46.0 min, 24.0% of a compound has decomposed. What is the half-life of this reaction assuming first-order kinetics?
t1/2 =
min
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Transcribed Image Text:of 25 After 46.0 min, 24.0% of a compound has decomposed. What is the half-life of this reaction assuming first-order kinetics? t1/2 = min Activate W Go to Settings contact us help about us careers privacy policy terms of use
Expert Solution
Step 1:

For a first order reaction , the integrated rate equation  is 

K = 2.303/t log[ a/(a-x) ]

K = rate constant

t = time 

a = initial percentage of reactants

x = percentage decomposed

 

The relation between half - life ( t 1/2 ) and rate constant ( K ) is 

t 1/2 = 0.693 / K

 

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