2+9-3 1- lim 0

Q: х2-2х-3 6. lim х-з х2-4х+3

A:

Q: ² +8-3 =? lim x-1 x+1

A: We have to find limit. AS PER GUIDELINE WE HAVE TO SOLVE ONLY ONE QUESTION

Q: 4. lim 2* 5. lim 3*

A: 4). To evaluate the limit: limx→02x. Solution: We know that any number having power zero is equal to…

Q: х3+9х2+20х 4. lim х-3+ х2+x-12

A:

Q: lim 2х-4 п x- 2 × |

A: We have to determine the value of above limit. Please see the explanation below

Q: 3) lim x 2 + -32

A:

Q: lim 6+ -3

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Q: 23) lim (5x- 1) = 19 X4

A:

Q: 2-36 lim X→-6 X+6

A: Let L=limx→-6x2-36x+6        =-62-36-6+6=00indeterminate form∴ To get determinate form use i…

Q: ネメ+2 3メ+x+! Lim 8.

A: we have to find the limit of the given expression

Q: 2 -2 lim 12 - 1

A:

Q: lim 2 0 1 3.

A: Given:-   limz→0 ez-1-zz2

Q: (3- х)2 b) lim x-6- x+ 6

A: Calculate limit of part b

Q: 5 /-12 lim x-0 9-4/

A:

Q: x|メ-コ 7) lim メ3

A: We have to find the limit

Q: Find the limit.

A: Evaluate: limx→0 1x+4-14x

Q: 2 ( - 12/² + 1) In X 11) lim

A:

Q: 3 lim (1+ 4 x2

A: Given thatlimt→∞1+3x+4x2x. The objective of the problem is to solve the given limit.

Q: 0.Lim ュー)×40,2 メ-2 メ→o “波 (1+x) - 1 4)Lim *キX メーフ。

A: In this question , we can find the limit .

Q: メーマメ~8 21- Lim メャ4 メー4

A:

Q: 3-ух+6 lim x→3 х-3

A: The limit of a function at a point is the value of the function when the value of the variable is…

Q: 2 x²-9 lim x 3 x - 3

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Q: lim (5- x) 6- 3- 2- 2 3 6. 4.

A:

Q: lim(32-+ 5) 1, CAL lim (125+ 2) 2. * 3.

A: Since you have posted a question with multiple sub-parts, we will solve the first three subparts for…

Q: lim 3 - lim 4. 2x+3

A: on solving this we get

Q: 2 (x²+3) – 3 1- lim, 0 x²

A: limx→0(x2+3)-3x22

Q: 3 12 lim x-3 x - 4 8. Evaluate x4

A:

Q: lim - 6)(x + 6) X- 6 lim (x + 6) = 12 1. lim %3D

A: To prove the limit: limx→6x2-36x-6=12. Evaluating the left hand side of the limit.…

Q: lim(x-2)[(x^4-16)/(x^3-8)]3? -2x-4 =? x-2 x3 + 2x², lim

A:

Q: x² + 25- 13 lim x--12 x+12

A:

Q: (2х-1)12—1 lim x→1 X-1

A: Given,          limx→12x-112-1x-1

Q: 12 lim *-3 x - 4 8. Evaluate x4 3.

A:

Q: x²-16 -4 x +4 - ...lim تساوي

A:

Q: 51. lim (x- 2) *2-4 X+2+ lim r1/(x-1)

A:

Q: 4. lim メ→3 メ-3 5. lim メーラ X-1

A:

Q: (9 + x)-1 – 9-1 8. lim x→0

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: 7. lim 2 1 + (x-1)3 2 1 8. lim (x-1)

A: Find the limit of number 7 and 8 only

Q: x3-8 5. lim X→2 xー2

A:

Q: 3. lim 4" 4. lim 5 X +00 5. lim (0.2)* lim (0.2) 6.

A:

Q: (5х+6)(х- 2) lim x→-2* (x-2)(x+2) X -

A:

Q: (х— 3)2 Lim 2 X→0 X 7-2х 2 (-3

A: To find limx→∞x-32x22-2x-3.

Q: 2.x 2х2 +х — 1 lim X→-1 х+1

A: givenlimx→-12x2+x-1x+1solve 2x2+x-1 by factorization method=2x2+2x-x-1=2x(x+1)-1(x+1)=(x+1)(2x-1)

Q: x² – 9 lim x→-3- X +3

A:

Q: 2+ 31 + 2 2-1-2 24.) lim

A: To find The limit of the above

Q: Lim メ、+x-2 -『 メ -→1 2ナ+ メャ2

A:

Q: Lim X-8 メ→2 X-16

A:

Q: (x+1)3-1 lim 2一

A: Given that :-         lim x-->0  [x+12/3 - 1] / x       **  L - hospital rule :-   limx-->0…

Q: бх-9 lim х—5 х3-12.х+3

A:

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.