2)A 1300-kg sports car initially has a velocity of 35.2 m/s due south. The driver slams the brakes to stop over a 190 m distance. a) What is the magnitude of tihe car's acceleration, in m/s? ? 1300k aニー 36.13 m/ş? %3D 35.2 e/s b) What average net force magnitude was necessary to stop the car? 1300 (35.2m/3)². Fnet = ニ4,29N 2(190 m) c) Assuming the tires do not skid, what coefficient of static firiction between the tires and pavement is meeded? = xN =36.93m/2)(4.24 N) -15C. 5N %3D

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Chapter10: Systems Of Particles And Conservation Of Momentum
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Solve #2, includes: a, b, and c.

2)A 1300-kg sports car initially has a velocity of 35.2 m/s due south. The driver slams the brakes to stop
over a 190 m distance.
a) What is the magnitude of the car's acceleration, in m/s² ?
1300k
35.2 e/s
36.13 m/ş?
%3D
b) What average net force magnitude was necessary to stop the car?
1300 (35.2m/3)²
Fnet
= 4, 24N
%D
2(190 m)
c) Assuming the tires do not skid, what coefficient of static friction between the tires and pavement is
ineeded?
fs = N
=(36.93m/2)(4.24 N)
715C.58N
Transcribed Image Text:2)A 1300-kg sports car initially has a velocity of 35.2 m/s due south. The driver slams the brakes to stop over a 190 m distance. a) What is the magnitude of the car's acceleration, in m/s² ? 1300k 35.2 e/s 36.13 m/ş? %3D b) What average net force magnitude was necessary to stop the car? 1300 (35.2m/3)² Fnet = 4, 24N %D 2(190 m) c) Assuming the tires do not skid, what coefficient of static friction between the tires and pavement is ineeded? fs = N =(36.93m/2)(4.24 N) 715C.58N
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