2Al2O3 yields 4Al +3O2 delta H = 3351.5 kJ
what is the delta H for the formation of 10.2 g of Al2 O3
Enthalpy of reaction is equal to the difference in enthalpy of product and reactants.
Enthalpy of formation is the amount of energy required to form one mole of compounds from its elements at standard conditions.
Standard enthalpy of compound in elemental state is zero.
Number of moles is equal to the ratio of mass to molar mass.
To determine the enthalpy of reaction.
Balanced chemical reaction
The given enthalpy is of enthalpy of decomposition of Al2O3 and hence to obtained enthalpy of formation of Al2O3 the reaction is reversed and hence, enthalpy of formation is 3351.5kJ.
Mass of Al2O3=10.2g.
Molar mass of Al2O3=101.96g/mol.
From the balanced chemical reaction 2 mole of Al2O3 absorb heat 3351.5kJ.
2 mole of Al2O3 absorb heat=
Number of moles of Al2O3=
Number of moles of Al2O3=
Enthalpy of formation of Al2O3=
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