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2V (1/2)W + X DH, = 10 kJ/mol (3/2)W + 4X → 2V + X + 3Y DH2 = -30 kJ/mol Z+ 4V → X DH3 = 20 kJ/mol %3D Calculate DH for: X+Z + 3Y Select one: O a. 20 kJ/mol O b.0 kJ/mol O C. -10 kJ/mol O d. -20 kJ/mol

2V (1/2)W + X DH, = 10 kJ/mol (3/2)W + 4X → 2V + X + 3Y DH2 = -30 kJ/mol Z+ 4V → X DH3 = 20 kJ/mol %3D Calculate DH for: X+Z + 3Y Select one: O a. 20 kJ/mol O b.0 kJ/mol O C. -10 kJ/mol O d. -20 kJ/mol

Physical Chemistry
Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.19E: What arethe differencesbetween an open, a closed, and an isolated system?Describe an example of...
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2V (1/2)W + X DH, = 10 kJ/mol (3/2)W + 4X → 2V + X + 3Y DH2 = -30 kJ/mol %3D Z + 4V → X DH3 = 20 kJ/mol %3! Calculate DH for: X→Z + 3Y Select one: O a. 20 kJ/mol O b. 0 kJ/mol O c. -10 kJ/mol O d. -20 kJ/mol O e. 10 kJ/mol
Transcribed Image Text:2V (1/2)W + X DH, = 10 kJ/mol (3/2)W + 4X → 2V + X + 3Y DH2 = -30 kJ/mol %3D Z + 4V → X DH3 = 20 kJ/mol %3! Calculate DH for: X→Z + 3Y Select one: O a. 20 kJ/mol O b. 0 kJ/mol O c. -10 kJ/mol O d. -20 kJ/mol O e. 10 kJ/mol
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