3-33. A medical linear accelerator is used to accelerate elec- trons to create high-energy beams that can destroy tumors with minimal impact on surrounding healthy tissue. The beam energy fluctuates between 200 and 210 MeV (million electron volts). The cumulative distribution function is F(x) = 0 {X- x < 200 0.1.x20 200 ≤x≤210 x > 210 Determine the following. (a) P(X<209) (b) P(200< X<208) (c) P(X> 209)
3-33. A medical linear accelerator is used to accelerate elec- trons to create high-energy beams that can destroy tumors with minimal impact on surrounding healthy tissue. The beam energy fluctuates between 200 and 210 MeV (million electron volts). The cumulative distribution function is F(x) = 0 {X- x < 200 0.1.x20 200 ≤x≤210 x > 210 Determine the following. (a) P(X<209) (b) P(200< X<208) (c) P(X> 209)
Chapter6: Exponential And Logarithmic Functions
Section6.8: Fitting Exponential Models To Data
Problem 3TI: Table 6 shows the population, in thousands, of harbor seals in the Wadden Sea over the years 1997 to...
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Parts a-f
![3-33. A medical linear accelerator is used to accelerate elec-
trons to create high-energy beams that can destroy tumors
with minimal impact on surrounding healthy tissue. The beam
energy fluctuates between 200 and 210 MeV (million electron
volts). The cumulative distribution function is
0
fo..
F(x) =
x < 200
0.1x20 200 ≤x≤210
x > 210
Determine the following.
(a) P(X<209) (b) P(200<x<208) (c) P(X> 209)
(d) What is the probability density function?
(e) Graph the probability density function and the cumulative
distribution function.
(f) Determine the mean and variance of the beam energy.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa589a0b1-5940-47b0-b798-8fa24b0ff23c%2F484a1da1-b7a9-461f-a2b2-2c87be6966e0%2Fityyu2v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3-33. A medical linear accelerator is used to accelerate elec-
trons to create high-energy beams that can destroy tumors
with minimal impact on surrounding healthy tissue. The beam
energy fluctuates between 200 and 210 MeV (million electron
volts). The cumulative distribution function is
0
fo..
F(x) =
x < 200
0.1x20 200 ≤x≤210
x > 210
Determine the following.
(a) P(X<209) (b) P(200<x<208) (c) P(X> 209)
(d) What is the probability density function?
(e) Graph the probability density function and the cumulative
distribution function.
(f) Determine the mean and variance of the beam energy.
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