A manager is interested in testing whether three populations of interest have equal population means. Simple random samples of size 10 were selected from each population. The following ANOVA table and related statistics were computed: Groups Sample 1 Sample 2 Sample 3 Source Between Groups Within Groups Total Count 10 10 10 SS 578.78 794.36 1,373.14 ANOVA: Single Factor Summary Sum 507.18 405.79 487.64 ANOVA of 2 27 29 Average 50.72 40.58 48.76 MS 289.39 29.42 F 9.84 Variance 35.06 30.08 23.13 p-value 0.0006 F-crit 3.354 Conduct the appropriate test of the null hypothesis assuming that the populations have equal variances and the populations are normally distributed. Use a 0.05 level of significance. O Using the F test approach, because F-3.354 < critical F-9.84, we reject the null hypothesis and conclude that the population means are not all equal. O Using the F test approach, because F-3.354 < critical F-9.84, we do not reject the null hypothesis and conclude that the population means are all equal. O Using the F test approach, because F= 9.84> critical F = 3.35, we reject the null hypothesis and conclude that the population means are not all equal. O Using the F test approach, because F-9.84 critical F= 3.35, we do not reject the null hypothesis and conclude that the population means are all equal.
A manager is interested in testing whether three populations of interest have equal population means. Simple random samples of size 10 were selected from each population. The following ANOVA table and related statistics were computed: Groups Sample 1 Sample 2 Sample 3 Source Between Groups Within Groups Total Count 10 10 10 SS 578.78 794.36 1,373.14 ANOVA: Single Factor Summary Sum 507.18 405.79 487.64 ANOVA of 2 27 29 Average 50.72 40.58 48.76 MS 289.39 29.42 F 9.84 Variance 35.06 30.08 23.13 p-value 0.0006 F-crit 3.354 Conduct the appropriate test of the null hypothesis assuming that the populations have equal variances and the populations are normally distributed. Use a 0.05 level of significance. O Using the F test approach, because F-3.354 < critical F-9.84, we reject the null hypothesis and conclude that the population means are not all equal. O Using the F test approach, because F-3.354 < critical F-9.84, we do not reject the null hypothesis and conclude that the population means are all equal. O Using the F test approach, because F= 9.84> critical F = 3.35, we reject the null hypothesis and conclude that the population means are not all equal. O Using the F test approach, because F-9.84 critical F= 3.35, we do not reject the null hypothesis and conclude that the population means are all equal.
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter8: Sequences, Series, And Probability
Section8.7: Probability
Problem 5E: List the sample space of each experiment. Rolling one die and tossing one coin
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Transcribed Image Text:12
A manager is interested in testing whether three populations of interest have equal
population means. Simple random samples of size 10 were selected from each population.
The following ANOVA table and related statistics were computed:
Groups
Sample 1
Sample 2
Sample 3
Source
Between Groups
Within Groups
Total
Count
10
10
10
SS
578.78
794.36
1,373.14
ANOVA: Single Factor
Summary
Sum
507.18
405.79
487.64
ANOVA
df
27
29
Average
50.72
40.58
48.76
MS
289.39
29.42
F
9.84
Variance
35.06
30.08
23.13
p-value
0.0006
F-crit
3.354
Conduct the appropriate test of the null hypothesis assuming that the populations have
equal variances and the populations are normally distributed. Use a 0.05 level of
significance.
O Using the F test approach, because F-3.354 < critical F-9.84, we reject the null hypothesis and
conclude that the population means are not all equal.
O Using the F test approach, because F= 3.354 < critical F=9.84, we do not reject the null
hypothesis and conclude that the population means are all equal.
O Using the F test approach, because F-9.84> critical F - 3.35, we reject the null hypothesis and
conclude that the population means are not all equal.
O Using the F test approach, because F = 9.84 critical F= 3.35, we do not reject the null hypothesis
and conclude that the population means are all equal.
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