3 butterflies are crossed with the line 5 butterflies and they produce all extra-long bodies, what do you about the butterflies produced from a cross between lines 1 and 5? f of the offspring would have wild-type bodies and half of the offspring would have extra-long bodies. re information is needed to answer this question. ne of the offspring would be mutant (extra long). offspring would be mutant (extra long). information provided, how many genes are defined among these five mutant strains of butterflies?
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- Aliens with orang eye color allele (o) is recessive to the dominant black eye color allele (O). The locus of the orange gene from 10 pure breed orange eyes aliens and 10 pure breed black eyes aliens. You notice a difference in the DNA sequence linked to each allele of the orange gene and you decide to use it as a physical marker to follow recombination between this sequence linked to the orange gene. These sequences consist of short tandem repeat (STR) with two different number of repeats, each associated with one of the two orange gene alleles. a PCR test distinguishes the 10 repeat STR and the 6 repeat STR associated with the O and o alleles respectively. Using primers on each side of the STRs you can amplify by PCR this sequence and visualizing the size of the 10 repeat and 6 repeat STRs in an electrophoresis gel. You can follow the two STR sequences (10 and 6 repeats) linkage and recombination frequencies with the orange gene locus. The black eye aliens yield a PCR fragment that is…You are attempting to genotype a series of cells at gene A through restriction enzyme digestion. You know that the wild type allele “A” has 2 restriction enzyme cutting sites, creating bands that are 100bp, 200bp, and 300bp. A mutation creating allele “a” removes one of these cutting sites, creating bands that are 100bp and 500bp. How many separate bands would you expect to see on a gel for a cell that is heterozygous Aa? please show work. thanksIf you had the ability to do gene editing with ONE gene for the betterment of human kind, which one would you choose, and why? Assume you could either change an abnormal allele associated with a disease, such as the cystin gene associated with Cystic Fibrosis to its normal wild type, or add a pre-existing human allele to a genome.
- This research exploited the principles of Mendelian genetics combined with the MCR technique to genetically manipulate fruit flies. Now, suppose you do a similar experiment. You perform two crosses: one that allows for Mendelian patterns of inheritance, and another that uses MCR with CRISPR-Cas9 to genetically edit the eye color of fruit flies. In fruit flies, the gene for eye color is located on the X chromosome. Red eyes (wild type, w+) are dominant to white eyes (mutant, w-). Let’s see how well you can predict genotype and phenotype ratios resulting from the two crosses. Genetic cross 1 (without MCR): Cross between a white-eyed male and a homozygous red-eyed female. Genetic cross 2 (with MCR): Cross between an MCR-element (carries the CRISPR-Cas9 construct) white-eyed male and a homozygous red-eyed female. Keep in mind, this technology converts a heterozygous genotype to a homozygous recessive genotype. Drag the labels to the table to fill in the genotypic and phenotypic ratios.Genes D, E and F are located on the same chromosome. From a three-point testcross mapping experiment, the following phenotypes were observed in the offspring: D E F 365 d E F 3 d e f 367 D e f 4 d E f 110 D E f 25 D e F 105 d e F 21 1. Which is the correct gene sequence? A. EFD B. DEF C. EDF D. FED 2. What is the distance between D and E in mu? 3. What is the distance between F and E in mu? 4. What is the distance between D and F in mu? 5. What is the coefficient of coincidence?The coloration of calico cats is also the result of the inactivation of one of a female cat's sex chromosomes. In females, two X chromosomes are present in all cells but only one is active, the inactive one is called a BARR BODY. This is why the coat color is random, even among cloned calico cats that have identical genomes. Calico is a coat color found in cats, which is caused by a SEX-LINKED, CODOMINANT allele. KEY: B = Black R = Orange BR = Calico The following genotypes are possible; Female cats can be black XBXB, orange XRXR, or calico XBXR Male cats can be black XBY or orange XRY If you are a cat breeder, what type of parents should you choose to have the MOST number of calico kittens?
- Achondroplasia is a form of dwarfism that is inherited in humans as an autosomal dominant disorder. A survey in a small country showed that, within a two-year period, there were 24 children with normal parents born with this disorder out of a total of 16,789 births. What is the mutation rate in mutations/locus/generation? answer to the nearest 0.0001.A RFLP is discovered that is linked to the gene for Duchenne’s muscular dystrophy (DMD). DMD is an X-linked, recessive trait. The RFLP is 2 map units from the gene for DMD. Consider the following pedigree and Southern blot using a probe that hybridizes to the RFLP. Which band/s is/are associated with DMD? What is the genotype for individuals 3 and 4? (Remember, this is an X linked disease, so use X’s and Y’s to denote). Individual 9 married a man who does NOT have muscular dystrophy, and she is pregnant. DMD is an X-linked trait. What is the probability for their child to have DMD? An amniocentesis is performed and it is determined that 9’s child in utero has only a 10 kb band that hybridizes to the same probe used above. What can you say about the child now?When you are visiting the local pet store you start talking to them about their Ceti alpha-5 eel colony. They tell you that some eels have red antennas, some have white antennas, and some have pink antennae. Whenever you cross an eel with red antennae to an eel with white antennae you only recover eels with pink antennae. If you assume antennae color is under the control of one gene and you cross two eels with pink antennae what would you predict would be the genotypes and phenotypes of the progeny? How would you explain these results? (Describe why the expected results from ‘a’ would happen.)
- There are two genetic disorders that result from mutation in imprinted genes: Prader-Willi syndrome, Angelman syndrome. Angelman syndrome results from deletion of UBE3A, which is a gene imprinted such that only the maternal copy is expressed. In the pedigree above, individual I-1 is heterozygous for a deletion of UBE3A and does not have Angelman syndrome. Individual I-2 is homozygous wild type for UBE3A. Which individuals in the pedigree are at risk for exhibiting Angelman syndrome, if any? (Who could potentially have the syndrome, based on what alleles it is possible for them to inherit and express?) Question 8 options: Only I-1 could have been at risk. If he does not have the syndrome, no one in the pedigree could. Only III-1 is at risk I-1, II-2, and III-1 are all at risk Only II-2 is at risk No one in the pedigree is at risk Both II-2 and III-1 are at…The original gene order on the chromosome for eight linked genes is A B C D E F G H. What would the gene order be after an A through C duplication followed by a D through F inversion? a. A B C D E F G H b. A B C A B C D E F G H c. A B C A B C D F E G H I d. A B C A B F E D G H e. A B C A B C F E D G HYou conduct a series of two-point mapping crosses involving five genes located on chromosome III and obtain the following percentage of recombinant offspring: h-cu eyg-h eyg-cu rai-eyg rai-h rai-cu th-cu th-h th-eyg th-rai 23.5% 9.0% 14.5% 18.5% 9.5% 33.0% 6.8% 16.7% 7.7% 26.2% The rai gene is at the near end of the chromosome. Gene th is between which two genes? A. eyg and cu B. rai and cu C. h and cu D. rai and h