3- Implement onContextItemSelected(). When the user selects a menu item, the system calls this method so you can perform the appropriate action.
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- Write a program that displays heads (H) or tails (T) for each of ninecoins, as shown in Figure 12.31c–d. When a cell is clicked, the coin is flipped.Write a custom cell class that extends Label. In the initializer of the class, bindthe event <Button-1> with the method for flipping the coin. When the program starts, all cells initially display H.import bridges.base.ColorGrid;import bridges.base.Color;public class Scene {/* Creates a Scene with a maximum capacity of Marks andwith a background color.maxMarks: the maximum capacity of MarksbackgroundColor: the background color of this Scene*/public Scene(int maxMarks, Color backgroundColor) {}// returns true if the Scene has no room for additional Marksprivate boolean isFull() {return false;}/* Adds a Mark to this Scene. When drawn, the Markwill appear on top of the background and previously added Marksm: the Mark to add*/public void addMark(Mark m) {if (isFull()) throw new IllegalStateException("No room to add more Marks");}/*Helper method: deletes the Mark at an index.If no Marks have been previously deleted, the methoddeletes the ith Mark that was added (0 based).i: the index*/protected void deleteMark(int i) {}/*Deletes all Marks from this Scene thathave a given Colorc: the Color*/public void deleteMarksByColor(Color c) {}/* draws the Marks in this Scene over a background…How to fix this code to work... from tkinter import *from tkinter import ttkfrom tkinter import messagebox class Student: def __init__(self, id, fn, ln, dob, m='undefined'): self.id = id self.firstName = fn self.lastName = ln self.dateOfBirth = dob self.major = m list_of_student = []window = Tk()window.geometry("800x750")window.title("Simple Student Management System")list_of_students = []id = 1001 def add_student(): global list_of_students global id if FirstnameEntry.get() =='': messagebox.showerror('erorr', "First name is required") return if LastnameEntry.get() =='': messagebox.showerror('erorr', "Last name is required") return if DateofbirthEntry.get() =='': messagebox.showerror('erorr', "Date of Birth is required") return if MajorEntry.get() =='': instance = Student(id, FirstnameEntry.get(), LastnameEntry.get(), DateofbirthEntry.get()) else: instance = Student(id, FirstnameEntry.get(), LastnameEntry.get(),…
- Using javascript getElementByClass- write a simple programe whereby each time a player gets shot by a bullet, the player loses a life and a 'live' is remove from the three 'lives'.If the player loses all three lives, display and print 'game over'.Display 'play again' message to restart th game. <ul class = "lives"> <li></li> <li></li> <li></li> </ul>Stack CreateStack(S) push (S, 10) push (S, 15) push (S, 20) x = top (S) push (S, x + 5) x = pop (S) + top (S) push (S, x – pop (S)) push (S, pop (pop (S))) push (S, x – top (S)) push (S, push(S, x) – top (S)) After executing the given codes above, answer the questions and explain. ThanksHow do I fix this code in order for it to run? BusFareHandler.java package BusFare; public interface BusFareHandler { /** * Initializes your available change. * * * create a MaxHeap with a 1,5,10,25,50,100 coin randomly inserted */ public void grabChange(); /** * get the largest ( in this case the 100 cent ) coin from your maxHeap * * @return max */ public int getMaxFromHeap(); /** * (1) The param for this method should be the result returned from getMaxFromHeap() * * (2) RECURSIVSELY build up the bus fare. * * * (3) Constraint: Bus only accepts 5,25,50,100 cent coins, but you should have other coins in your collection. * * * @param coin */ public int payBusFare(int coin); //week1 test recursive call by selecting next element out of a sorted array instead of calling getMaxFromHeap() } BusFareHandlerImpl.java package BusFare; import MaxHeap.MaxHeap; import MaxHeap.MaxHeapImpl; import java.util.Random; public class BusFareHandlerImpl implements…
- JAVA //3B// Implement a method public static ArtObject[] filterByStatus(ArtObject[] objects, char status) that returns a new array of ArtObject. This array should contain those art objects that have the specified status. char[] status = new char[] {'s', 's', 's', 'u', 'u', 'u', 's', 's', 'u', 'u', 'u', 'u', 's', 's', 'u', 's', 's', 's', 's', 'u', 'u', 's', 's', 's', 's', 'u', 's', 's', 'u', 'u', 's', 'u', 'u', 's', 's', 'u', 'u', 's', 's', 'u'}; double[] prices = new double[] {600, 6000, 1500, 1000, 1000, 1500, 2500, 1800, 1500, 400, 4000, 2000, 5000, 1000, 2000, 6000, 800, 1000, 1500, 1000, 1500, 500, 1500, 1500, 1500, 8000, 3000, 8000, 2500, 5000, 1500, 5000, 10000, 2000, 1500, 3500, 1500, 2500, 2500, 2500}; plz i need an expert to solve it, I do not need the Indian People who use the AI to answer this questionComplete the Link class by writing the methods described below. Do not use loops, or create any more methods (other than those specified), class, or instance variables.public class Link{private Link next; //null if this is the last linkprivate int value;public Link(Link n, int v){next = n;value = v;}} -------------------------------------------------------------------------------------------------------------------------------------------------------Do not use loops, or create any more methods (other than those specified), class, or instance variables. 1) Write a recursive instance method count that takes no parameters and returns an int. Return the number of links that hold the value zero, with the exception that the last link in the list is not included in the count. For example, for the linked list, {(first) 5→0→3→1→0→0 (last)} it would return the value 2. 2) Write a recursive instance method isSorted that takes a Link parameter and determines whether a linked list is sorted in…In the Lights Out Puzzle class, write a method copy(self) that returns a new LightsOutPuzzle object initialized with a deep copy of the current board. Changes made to the original puzzle should not be reflected in the copy, and vice versa.>>> p = create_puzzle(3, 3)>>> p2 = p.copy()>>> p.get_board() == p2.get_board()True>>> p = create_puzzle(3, 3)>>> p2 = p.copy()>>> p.perform_move(1, 1)>>> p.get_board() == p2.get_board()FalseIn the LightsOutPuzzle class, write a method successors(self) that yields all successors of the puzzle as (move, new-puzzle) tuples, where moves themselves are (row, column) tuples. The second element of each successor should be a new LightsOutPuzzle object whose board is the result of applying the corresponding move to the current board. The successors may be generated in whichever order is most convenient.>>> p = create_puzzle(2, 2)>>> for move, new_p in p.successors():...…
- please remove break to exit the loop. Find another way to exit loops without using breaks in the WindowApp class. WindowApp class import java.io.*;import java.util.Scanner; class WindowApp{public static void main(String [] args) {try {Window [] window = read();System.out.println("Creating window data from file data, loading it into an array, and displaying");for (int i= 0; i < window.length; i++) {if(window[i] == null) {break;}System.out.println("--- Window " + i+ ": " + window[i]);window[i].display();System.out.println();}System.out.println("\nTurning on visibility");for (int i= 0; i < window.length; i++) {if(window[i] == null) {break;}System.out.println("--- Window " + i+ ": " + window[i]);window[i].setVisible(true);window[i].displayNormal();System.out.println();}System.out.println("\nResizing (flipping width and height) and displaying");for (int i= 0; i < window.length; i++) {if(window[i] == null) {break;}window[i].resize(window[i].getHeight(),…class ADSockDrawer(object): def__init__(self): self.drawer = AD() defadd_sock(self, color): """Adds a sock of the given color to the drawer. Do it in one line of code.""" # YOUR CODE HERE defget_pair(self, color): """Returns False if there is no pair of the given color, and True if there is. In the latter case, it removes the pair from the drawer. Do it in 5 lines of code or less.""" # YOUR CODE HERE @property defavailable_colors(self): """Lists the colors for which we have at least two socks available. Do it in 1 line of code.""" # YOUR CODE HEREA Memory Matching Game in java code with a 4x4 grid of Squares that when you click on a square it shows a number. It would have to be 2 of each number 1-8 and if the two squares that are clicked match then the squares stay on the grid. If they do not match after picking 2 squares they flip back over