Write the chemical equation for a pentanoate ion acting as base when it reacts with hydrochloric acid (HCI).Which is formula of this rule of reaction? 1) Write the chemical equation for the reaction of propanoic acid with 1-butanol (an alcohol).The formula of 1-butanol is CH3-CH2-CH2-CH2-OH.CH3CH₂-C-0-HICH SCHQ, CHR₂CH₂-OH-CH₂CH₂-C-0-CH₂CH2CH₂CH3+H₂0f요R-C-OH+H-OR' =R-C-OR" + H2O2) Write the chemical equation for the reaction of ethanoic acid with N-methylethanamine.CH3-C-0-H+H-WCH₂CH3 CH3 -C-NCH₂CH3 + H₂0CH3CH 33) Write the chemical equation for a pentanoate ion acting as base when it reacts with hydrochloric acid (HCI).요CH3CH₂CH₂CH₂C-0² + H61ZCH3CH₂CH₂CH₂C-OH + cl4) Write the chemical equation for the decarboxylation of 2-methyl-propanoic acid.CH3CH-CH32-0-HCH3CH₂ CH3 + CO₂5) Write the chemical equation for the reaction of propanoic acid with water.11CH3CH₂-C-OH(aq) + H₂0 (1) CH3CH₂-C-0 (99) + H₂0 (aq)11R-C-OH + H₂₂0 2²² R-²-0² + H₂0²Carboxylic acid(acid form)Carboxylate ion(base form)3

Here is a neutralization reaction where the base (pentanoate ion) reacts with the acid…

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3) Write the chemical equation for a pentanoate ion acting as base when it reacts with hydrochloric acid (HCI).

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter19: Aldehydes And Ketones: Nucleophilic Addition Reactions

Section19.SE: Something Extra

Problem 28VC

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Question

100%

Write the chemical equation for a pentanoate ion acting as base when it reacts with hydrochloric acid (HCI).

Which is formula of this rule of reaction?

1) Write the chemical equation for the reaction of propanoic acid with 1-butanol (an alcohol).
The formula of 1-butanol is CH3-CH2-CH2-CH2-OH.
CH3CH₂-C-0-HICH SCHQ, CHR₂CH₂-OH-CH₂CH₂-C-0-CH₂CH2CH₂CH3+H₂0
f
요
R-C-OH+H-OR' =R-C-OR" + H2O
2) Write the chemical equation for the reaction of ethanoic acid with N-methylethanamine.
CH3-C-0-H+H-WCH₂CH3 CH3 -C-NCH₂CH3 + H₂0
CH3
CH 3
3) Write the chemical equation for a pentanoate ion acting as base when it reacts with hydrochloric acid (HCI).
요
CH3CH₂CH₂CH₂C-0² + H61ZCH3CH₂CH₂CH₂C-OH + cl
4) Write the chemical equation for the decarboxylation of 2-methyl-propanoic acid.
CH3CH-
CH3
2-0-HCH3CH₂ CH3 + CO₂
5) Write the chemical equation for the reaction of propanoic acid with water.
11
CH3CH₂-C-OH(aq) + H₂0 (1) CH3CH₂-C-0 (99) + H₂0 (aq)
11
R-C-OH + H₂₂0 2²² R-²-0² + H₂0²
Carboxylic acid
(acid form)
Carboxylate ion
(base form)
3

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