3. A 100.0 mL sample of ground water was treated to convert the iron present to Fe2+. Addition of 25.00 mL of 0.002412 M K2Cr2O7 resulted in the reaction below. 6Fe2+ + Cr2O72 - + 14H+ → 6Fe3+ + 2Cr3+ + 7H2O The excess K2Cr2O7 was back-titrated with 8.12 mL of 0.00859 M Fe2+ solution. What is the concentration of Fe in the sample in parts per million?
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- 2. 100.0-mL sample of spring water was treated to convert any iron present to Fe2*. Addition of 25.00 mL of 0.002107 M K2Cr207 resulted in the reaction 6FE2+ + Cr20,2- + 14H* ® 6F€³+ + 2Cr3+ + 7H2O The excess K2C1207 was back-titrated with 7.47 mL of a 0.00979 M Fe2+ solution. Calculate iron concentration (molarity) in the sample.A 100.0-mL sample of spring water was treated to convert any iron present to Fe21. Addition of25.00-mL of 0.002517 M K2Cr2O7 resulted in the reaction6Fe2+ + Cr2O7 2- + 14H+ → 6Fe3+ + 2Cr3+ + 7H2OThe excess K2Cr2O7 was back-titrated with 8.53 mL of 0.00949 M Fe2+ solution. Calculate the concentration of iron in the sample in parts per million.To analyze the amount of iron (Fe; Mw = 55.85 g/mol) contained in an ore sample, the sample was digested with acid and diluted to 50 mL with water. This solution was then treated with 25.00 mL of 0.2922 M EDTA. The excess EDTA was back titrated with 6.47 mL of 0.0843 M Zn2+ to reach the equivalence point. How many grams of Fe contained in the ore sample?
- A 0.5962 g sample of iron ore is dissolved in perchloric acid (HCIO4). All iron present is oxidized to Fe3*. The solution is filtered to remove solid matrix materials and made basic with addition of ammonium hydroxide. The iron precipitates as the Fe(OH)3.XH2O gel. The precipitate is collected in a cistern crucible and ignited to produce Fe203. What is the wt. % of iron in the sample if the analysis produced 0.3210 g Fe2O3? Fe3+ + 3 OH → Fe,O3 + → Fe203 H2 18.83% 9.415% 56.49% O 37.66%The amount of Fe (55.85g/mole)in a 16.9776-g sample of an ore was determined by a redox titration with K2Cr2O7. The sample was dissolved in HCI and the iron brought into the +2 oxidation state using a Jones reductor. Titration to the diphenylamine sulfonic acid end point required 43.7238 mL of 0.1351 M K2Cr2O7. Report the iron content of the ore as %w/w Fe2O3 (159.69g/mole) (Answers should be written in 2 decimals place and do not include the UNIT)A 0.9352g sample of ore containing Fe³+, Al³+ and Sr²+ was dissolved and made up to 500.00 mL. The analysis of metals was performed using complexation volumetry. Initially, an aliquot of 50.00 mL had its pH adjusted to 1.0 and titrated with a standard 0.03145 mol/L EDTA solution, requiring 6.95 mL to reach the end point. Subsequently, another 25.00 mL aliquot was buffered at pH=5 and titrated with the same EDTA solution, requiring 6.24 mL to reach the end point. Finally, a third aliquot of 25.00 mL was titrated at pH=11, requiring 11.10 mL of the same EDTA solution to complete the titration. Given the molar masses: Fe=55.845 g/mol; Al-26.982 g/mol and Sr-87.620 g/mol. a) Determine the percentage of each of the metals in the sample. b) Explain why the change in pH allows the determination of the three ions in this sample.
- An alloy containing Ni, Fe and Cr was analyzed by a complexation titration using EDTA as titrant. A 0.7176 g sample of the alloy was dissolved in HNO3 and diluted to 250 mL in a flask. A 50.00 mL aliquot of the sample, treated with pyrophosphate to mask Fe and Cr, required 26.14 mL of 0.05831 M EDTA to reach the murexide endpoint. A second 50.00 mL aliquot was treated with hexamethylenetetramine to mask Cr and titration with 0.05831 M EDTA required 35.43 mL to reach the murexide endpoint. Finally, a third 50.00 mL aliquot was treated with 50.00 mL of 0.05831 M EDTA and titrated back to the murexide endpoint with 6.21 mL of 0.06316 M Cu(II). the weight percentages of Ni, Fe and Cr in the alloy.A Chemist collected a 0.4891-g sample of an ore for Fe determination by a redox titration with K2Cr2O7.The ore was carefully crushed prior to weighing and dissolved in HCl and using a Jones reductor the ironin the sample was brought into the +2 oxidation state. After titration with diphenylamine sulfonic acid,itrequired 36.92 mL of 0.02153 M K2Cr2O7 to reach the end point. Show your solution why 77.86% is the iron content of the ore as %w/w Fe2O3.A Chemist collected a 0.4891-g sample of an ore for Fe determination by a redox titration with K2Cr2O7.The ore was carefully crushed prior to weighing and dissolved in HCl and using a Jones reductor the ironin the sample was brought into the +2 oxidation state. After titration with diphenylamine sulfonic acid,itrequired 36.92 mL of 0.02153 M K2Cr2O7 to reach the end point. Calculate the iron content of the ore as%w/w Fe2O3
- The amount of iron in a meteorite was determined by a redox titration using KMnO4 as the titrant. A 0.4185 -g sample was dissolved in acid and the liberated Fe3+ quantitatively reduced to Fe2+, using a reductor column. Titrating with 0.0044 M KMnO4 requires 28.76 mL to reach the end point. Determine the %w/w Fe2O3 in the sample of meteorite. (Fe = 55.845 amu, Fe2O3 = 159.69 g/mol2) A 100.0-mL sample of spring water was treated to convert any iron present to Fe2*. Addition of 25.00 mb. of 0.008 M K2Cr207 resulted in the reaction 6F22+ + Cr2O72- + 14H*2 6FE3+ + 2Cr3+ + 14H2O The excess K2C12O7 was back-titrated with 8.53 ml of 0.00949 M Fe2* şolution. Calculate the molar concentration of iron in the sample.Chromel is an alloy composed of nickel, iron, and chromium. A 0.6392-g sample was dissolved and diluted to 250.0 mL. When a 50.00-mL aliquot of 0.05173 M EDTA was mixed with an equal volume of the diluted sample, all three ions were chelated, and a 5.15-mL back-titration with 0.06139 M copper(II) was required. The chromium in a second 50.0-mL aliquot was masked through the addition of hexamethylenetetramine; titration of the Fe and Ni required 34.27 mL of 0.05173 M EDTA. Iron and chromium were masked with pyrophosphate in a third 50.0-mL aliquot, and the nickel was titrated with 24.31 mL of the EDTA solution. Calculate the percentages of nickel, chromium, and iron in the alloy. Percentage of nickel = % Percentage of iron = Percentage of chromium = % 10