3. A man heterozygous for both dominant traits of dimples (D) and free ear lobes (E) marries a woman without dimples and with attached ear lobes. What are the genotypic and phenotypic ratios of the offspring? What is the probability of the offspring being recessive for both characteristics? D = Dimples; d = no dimples Symbols E = Free ear lobes; e = attached ear lobes Parental Cross Genotypic Ratios Phenotypic Ratios X Punnett Square What is the probability of the offspring being recessive for both characteristics?

3. A man heterozygous for both dominant traits of dimples (D) and free ear lobes (E) marries a woman without dimples and with attached ear lobes. What are the genotypic and phenotypic ratios of the offspring? What is the probability of the offspring being recessive for both characteristics? D = Dimples; d = no dimples Symbols E = Free ear lobes; e = attached ear lobes Parental Cross Genotypic Ratios Phenotypic Ratios X Punnett Square What is the probability of the offspring being recessive for both characteristics?

Name: Step by step 3. A man heterozygous for both dominant traits of dimples
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Description: Step by step 3. A man heterozygous for both dominant traits of dimples (D) and free ear lobes (E) marries awoman without dimples and with attached ear lobes. What are the genotypic and phenotypic ratiosof the offspring? What is the probability of the

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 5GP

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1. If your genotype is Bb, what type of trait would you express as phenotype? a. dominant b. recessive c. both a and b d. neither a nor b 2. If your genotype is BB, what type of trait would you express as phenotype? a. dominant b. recessive c. both a and b d. neither a nor b 3. If a baby goat received a dominant gene for curly hair from one parent, and a recessive gene for straight hair from the other, which trait will the baby goat display? a. No hair b. Curly hair c. Straight hair d. Straight and curly hair 4. The allele for yellow seeds in pea plants, Y, is dominant. The allele for green seeds in pea plants, y, is recessive. Which combination would produce a plant with green seeds? a. YY b. Yy c. yY d. yy 5. In humans, the allele for brown eyes, B, is dominant over the allele for blue eyes, b. Which combination of alleles shown below could result in a…
2) Charlie doesn’t have a bent little finger (dominant trait) but his parents do. What is the phenotypic ratio among the parent’s children? ______________________
4.) A man and a woman have a child. The father is blood type A, and one of his parents was blood type A and the other was blood type O. The mother is blood type B, and one of her parents was blood type B, the other type O. Both the father and the mother are carriers of the Bombay allele. (Neither of the type-O grandparents were type O because of the Bombay allele – they had the regular type O genotype.) WhataretheoddsthattheirbabywillhavebloodtypeO? WhataretheoddsthattheirbabywillhavebloodtypeAB? (Hint – for this question, you should draw out a pedigree and fill in as much as you can for the genotypes of BOTH genes that are involved.)
4)If an individual is bald, so you can't tell whether or not they have a widow's peak, but neither parent has a widow's peak, which genotypes are possible? a)Group of answer choices b)Homozygous recessive c)Homozygous dominant d)Heterozygous e)Unable to determine
2) A researcher crossed a heterozygous yellow seed plant (Yy) and a recessive green seedplant (yy). Draw a Punnett Square and determine the genotype and phenotype ratios ofthe offspring.
4. The ruffed chicken has an under-chin wattle. A smooth wattle (S) is dominant over a wrinkled wattle (s). A red wattle (HR) is incompletely dominant with a white wattle (HW) so that an individual with HRHW will have a pink wattle. A chicken with a wrinkled red wattle is mated to a homozygous chicken with a smooth white wattle. What is the genotype and phenotype of the chicks?
7. The ability to roll your tongue (R) is dominant to lack of this ability (r). A. What is the genotype of a man who can roll his tongue if his father couldn’t? B. If a man who is heterozygous for tongue rolling marries a woman who is heterozygous, what would you predict for the genotypes and phenotypes of their children?
1. A cow is heterozygous for three genes (WwPp) where W-White, w-Brown, P-Polled, p-Horned. Give the phenotypic and genotypic ratio of their offspring if the cow is inter se mated. 2.A male Sahiwal (RRHH) is crossed with a female Angus (Rrhh). Where R-Red, r-Brown, H-Horned, h-polled. Give the phenotypic and genotypic ratio of their offspring.
3) The ability to curl ones’ tongue up on the sides (T) is dominant to not being able to roll your tongue (t). a. A woman who can roll her tongue marries a man who cannot. The first child has the same phenotype as the father, what are the genotypes of the mother, father, and this child? b. What is the probability that the second child won’t be able to roll it’s tongue?
4. The inheritance of coat colour in cattle controlled by multiple alleles with a dominance hierarchy as follows: S > sh > sc > s. The S allele produces a white band all over the cattle’s body known as ‘Dutch band’, the sh allele produces spots on the skin known as ‘Hereford’, the sc allele produces solid colour, and the s allele produces ‘Holstein’ spots. Homozygous ‘Dutch band’ males are cross to ‘Holstein’ females. The F1 females are crossed to ‘Hereford’ males of the shsc genotype. With the aid of genetic diagram, determine the expected genotypic and phenotypic frequencies in the F2 progeny.
1. In fruit flies, the phenotype for eye color is determined by a certain locus. E indicates the dominant allele and eindicates the recessive allele. The cross between a male wild-type fruit fly and a female white-eyed fruit flyproduced the following offspring.Wild-typeMaleWild-typeFemaleWhite-eyedMaleWhite-eyedFemaleBrown-eyedFemaleF1 0 45 55 0 1The wild-type and white-eyed individuals from the F1 generation were then crossed to produce the followingoffspring.F2 23 31 22 24 0(a) Determine the genotypes of the original parents (P generation) and explain your reasoning. You may usePunnett squares to enhance your description, but the results from the Punnett squares must be discussed inyour answer.(b) Use a Chi-squared test on the F2 generation data to analyze your prediction of the parental genotypes. Showall your work and explain the importance of your final answer.(c) The brown-eyed female in the F1 generation resulted from a mutational change. Explain what a mutation is,and discuss…
1. The probability of an offspring having all the recessive traits from the cross AaBBCc X AaBbCC is: a.one-sixteenth b.three-fourth c.zero d.nine-sixteenth 2. The probability of an offspring having all the dominant traits from the cross AaBBCc X AaBbCC is: a.three-fourth b.one-sixteenth c.nine-sixteenth d.zero