3. Find the molar fraction of HCI in vapors over solution of 1.86 g of HCI in 100 g of benzene. Total pressure over that solution equals at 293 K equals to 101 325 Pa. Henry's constant for HCl under this conditions equals to 4.195-10 kPa. Mc= 12.01 g-mol', M, 1.01 g mol, Mo = 35.45 g-mol.

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3. Find the molar fraction of HCI in vapors over solution of 1.86 g of HCI in 100 g of benzene. Total
pressure over that solution equals at 293 K equals to 101 325 Pa. Henry's constant for HCI under this
conditions equals to 4.195-10“ kPa". Mc = 12.01 g-mol", M = 1.01 g-molr, Ma= 35.45 g-mol.
Transcribed Image Text:3. Find the molar fraction of HCI in vapors over solution of 1.86 g of HCI in 100 g of benzene. Total pressure over that solution equals at 293 K equals to 101 325 Pa. Henry's constant for HCI under this conditions equals to 4.195-10“ kPa". Mc = 12.01 g-mol", M = 1.01 g-molr, Ma= 35.45 g-mol.
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