It takes 24.05 mL of 0.952 M NAOH to titrate a 15.00 ml sample of white vinegar (i.e. HC2H3O2).НС-Нз02(аq) + NaOH(aq) — Hz0() + NaC,Hҙ02(aq)2.а.What is the molar concentration of the vinegar?b. If the density of the solution is 1.05 g/mL, what is the percent by mass of the vinegar in thesolution?

Given data: Molarity of NaOH = 0.952 M Volume of NaOH = 24.05 mL Volume of vinegar = 15.00 mL…

It takes 24.05 mL of 0.952 M NaOH to titrate a 15.00 mL sample of white vinegar (i.e. HC2H3O2). HC,H302(aq) + NaOH(aq) → H20(1) + NaC,H302(aq) 2. а. What is the molar concentration of the vinegar? b. If the density of the solution is 1.05 g/mL, what is the percent by mass of the vinegar in the solution?

It takes 24.05 mL of 0.952 M NaOH to titrate a 15.00 mL sample of white vinegar (i.e. HC2H3O2). HC,H302(aq) + NaOH(aq) → H20(1) + NaC,H302(aq) 2. а. What is the molar concentration of the vinegar? b. If the density of the solution is 1.05 g/mL, what is the percent by mass of the vinegar in the solution?

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter3: Chemical Reactions

Section: Chapter Questions

Problem 151QRT: A mountain lake that is 4.0 km × 6.0 km with an average depth of 75 m has an H+(aq) concentration of...

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