3. Given the following data of the figure shown: P= 5.5 KN, L, = L, = L, = 2.5 m Strut BC = 100 mm wide x 20 mm thick L, Bar AD = 120 mm wide x 20 mm thick Allowable bolt shear stress = 120 MPa a) Determine the stress in strut BC in MPa. b) Compute the required minimum bolt L, diameter at C in mm. c) If the bolt at A has a diameter of 25 mm, determine the resulting bolt stress in MPa. TYPICAL JOINT

3. Given the following data of the figure shown: P= 5.5 KN, L, = L, = L, = 2.5 m Strut BC = 100 mm wide x 20 mm thick L, Bar AD = 120 mm wide x 20 mm thick Allowable bolt shear stress = 120 MPa a) Determine the stress in strut BC in MPa. b) Compute the required minimum bolt L, diameter at C in mm. c) If the bolt at A has a diameter of 25 mm, determine the resulting bolt stress in MPa. TYPICAL JOINT

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter5: Stresses In Beams (basic Topics)

Section: Chapter Questions

Problem 5.5.9P: A seesaw weighing 3 lb/ft of length is occupied by two children, each weighing 90 lb (see figure)....

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A seesaw weighing 3 lb/ft of length is occupied by two children, each weighing 90 lb (see figure). The center of gravity of each child is 8 ft from the fulcrum. The board is 19 ft long, 8 in. wide, and 1.5 in. thick. What is the maximum bending stress in the board?
An iron rod 4 m long and 0.5 cm2 in cross section stretches 1 mm when a mass of 225 kg is hang on it. Compute the modulus of elasticity of the iron. A. 176.58 GPa B. 169.81 Gpa C. 160.41 GPa D. 180.26 Gpa Please solve the Problem elaborately and Refer Machine Elements and Stresses Equations from the figures or use other shortcut Methods you have or you may Solve both or in more different methods the better ?. Your solution will be use as reference for my Future Board Exam preparation/review/study. Thank you so much dear your work will be appreciated much and rated excellently.
4-Find the stresses in each direction, also find the change in volume of the block of dimension 110 mm x 50 mm x 31 mm, subjected to 3 mutually perpendicular loads. The load along length, breadth and depth directions are 22 kN (tensile), 30 kN (compressive), 22 kN (compressive) respectively. Take E as 100 GPa, Poisson’s ratio as 0.3 The stress along length direction (Unit in MN/m2)= _____________ The compressive stress along width direction (Unit in MN/m2)= _____________ The compressive stress along depth direction (Unit in MN/m2)= _____________ The change in volume of the block is (unit in mm3) = ______________
A steel rod is stretched between two rigid walls and carries a tensile load of 5000 N at 20°C. If the allowable stress is not to exceed 130 MN/m² at -20 °C, what is the minimum diameter of the rod? Assume k = 11.7 µm/(m-°C); E = 200 Gpa A. 10.22 mm B. 11.22 mm C. 12.22 mm D. 13.22 mm Please solve the Problem elaborately and Refer Machine Elements and Stresses Equations from the figures or use other shortcut Methods you have or you may Solve both or in more different methods the better ?. Your solution will be use as reference for my Future Board Exam preparation/review/study. Thank you so much dear your work will be appreciated much and rated excellently.
a) If a pipe with an inner diameter of 36 mm is subjected to an axial load of 5.20 x 105 N and the maximum allowable stress in the pipe is 7.5 x 109 N/m2 , calculate the minimum wall thickness required for the pipe. Give your answer in millimetres (mm) to 2 decimal places. b)A wire with a Young’s Modulus, E, of 8.5 x 106 N/m2 and an original length of 1.5 m is under tension. If the wire length extension is 2.5 mm, calculate the stress in the wire. Give your answer in N/m2 to 2 decimal places.
1. Figure Q2a shows a hollow tube of rectangular cross-section subjected to an axial compressive load of 250 kN. The section dimensions are breadth, b = 0.12 m, depth, d = 0.05 m with an equal thickness on all sides, t = 0.003 m. Calculate the compressive stress σ in the tube. Give your answer in N/mm2 to 2 decimal places.
A wood pole of solid circular cross section (d = diameter) is subjected to a triangular distributed horizontal force of peak intensity q0 = 22 lb/in. (see the figure). The length of the pole is L = 7 ft , and the allowable stresses in the wood are 1800 psi in bending and 150 psi in shear. Determine the minimum required diameter of the pole based upon (a) the allowable bending stress, and (b) the allowable shear stress. Round your answers to three decimal places. (a) dmin = __ in. (b) dmin = __ in.
Please answer the problem completely. Show a free body diagram. Final answer: Shear stress = 3.2 mpa
Question 2) arm of Figure B from point x z plane, a horizontal angle of θ = 44 ° angled F = 26 kN size and a force C at the point z in the direction of M = 18 kn.m acts a moment in size. The lengths of the arm are also given as L 1 = 1.6 m and L 2 = 1.3 m . It is desired to determine the stress state of point A on the aa section taken from the arm. The radius r of the section is r=0.029 m and the shear modulus of the sleeve material is also G = 79 Gpa . According to this; Question 2-A) Find the shear stress at point A due to the shear force . ( Write your result in MPa .) Question 2-B) Find the shear stress due to the torsional moment at point A. ( Write your result in MPa .) Question 2-C) Find the normal stress caused by the normal force at point A ( Write your result in MPa .) Question 2-D) Find the normal stress caused by the bending moment at point A. (Your result MPa in the size of your font.)
Question 2) arm of Figure B from point x z plane, a horizontal angle of θ = 44 ° angled F = 26 kN size and a force C at the point z in the direction of M = 18 kn.m acts a moment in size. The lengths of the arm are also given as L 1 = 1.6 m and L 2 = 1.3 m . It is desired to determine the stress state of point A on the aa section taken from the arm. The radius r of the section is r=0.029 m and the shear modulus of the sleeve material is also G = 79 Gpa . According to this; Question 2-A) Find the shear stress at point A due to the shear force . ( Write your result in MPa .) Question 2-B) Find the shear stress due to the torsional moment at point A. ( Write your result in MPa .) Question 2-C) Find the normal stress caused by the normal force at point A ( Write your result in MPa .)
Question 2) arm of Figure B from point x z plane, a horizontal angle of θ = 44 ° angled F = 26 kN size and a force C at the point z in the direction of M = 18 kn.m acts a moment in size. The lengths of the arm are also given as L 1 = 1.6 m and L 2 = 1.3 m . It is desired to determine the stress state of point A on the aa section taken from the arm. The radius r of the section is r=0.029 m and the shear modulus of the sleeve material is also G = 79 Gpa . According to this; Question 2-C) Find the normal stress caused by the normal force at point A ( Write your result in MPa .) Question 2-D) Find the normal stress caused by the bending moment at point A. (Your result MPa in the size of your font.)
From the figure below, a shaft consists of different sections. Bar (a) is a hollow bar and has an outer d = 0.2m and thickness of 10 mm. Bar (b) is also a hollow bar with outer d = 0.15 m with same thickness as bar (a). If T1= 42,000 N-m and T2 = 18,000 N-m, Find the max shear stress in bar (b). Answer in MPa.