3. The decomposition of hydrogen iodide has an equilibrium constant of 1.84 x 102. What is the equilibrium pressure of hydrogen iodide if at equilibrium the hydrogen pressure and iodine pressure are 0.500 atm each? 2HIH₂ + Iz [H₂] [[2] [HI]² K= 1.84×10-² = (-5)(-5) x=3.69atm x2
3. The decomposition of hydrogen iodide has an equilibrium constant of 1.84 x 102. What is the equilibrium pressure of hydrogen iodide if at equilibrium the hydrogen pressure and iodine pressure are 0.500 atm each? 2HIH₂ + Iz [H₂] [[2] [HI]² K= 1.84×10-² = (-5)(-5) x=3.69atm x2
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.37PAE: Again the experiment in Exercise 12.33 was redesigned. This time, 0.15 mol each of N, and O2 was...
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