30 mm OF 10 mm 30 mm 10 mm X

Q: 200 mm 150 mm 100 mm 200 mm

A:

Q: 0.1 mm gap 20 Figuro 0

A: For solution refer below images.

Q: 9/16 inch is approximately equivalent to . mm. 19 17 14 12

A: The dial indicator is a traditional mechanical kind with a dial display that resembles a clock face…

Q: 80 mm 50 mm 2 1 7 15 mm 15 mm 3.

A: The Center of mass is a point where the sum of the moment of the weight of each particle is zero. It…

Q: 4000 N 3000 N B C 300 mm 100 mm 100 mm 十+

A: For question 1 option B is correct.  For question 2 option A is correct.  Steps are given in next…

Q: y 200 mm 200 mm + 150 mm- 125 mm 60 mm 125 mm 1.

A:

Q: 200 mm C 600 mm 200 mm

A: Area moment of inertia is a geometrical property that defines how different points are arranged with…

Q: 150 200 mm D mm 150 150 v2 mm mm 0 = 45° E 12.5 rad/s

A: Given data,θ=45°ω=10 rad/sOB=1502mm=0.2155mAB=350mm=0.3556mO'A=150=0.1524m

Q: 1. 100 mm 225 mm 75 mm 125 mm 50 mm

A: According to the details provided in the question, we need to calculate centroid.

Q: 600 mm 600 mm

A: given:

Q: 50 mm 30 mm 20 mm 40 mm * -60 mm- 40 mm x

A: GIVEN DATA- A COMPOSITE AREA GIVEN  WE HAVE TO FIND CENTROID OF AREA

Q: Fx A 75 mm 50 mm 150 mm 350 mm В F2 250 mm y

A:

Q: 20° F = 10 N 250 mm 20N B 60% 37.5 mm

A: The given system of force is – The component of 10 N forces is –

Q: Q1/B: Explain the following sketches

A: Given Inspection device To find Working

Q: A 150 mm B 240 mm 80 mm

A:

Q: 100 mm- 11.5 mm 7.5 mm N A 225 mm 11.5 mm (a)

A:

Q: Locate the centroid of the plane area shown.

A: The centroid of a 2d plane is the point at which the entire plane can be balanced on the tip of a…

Q: 25 mm R50mm 100 mm

A: Given

Q: 10 mm Y 15 mm 30 mm 40 mm 10 mm 15 mm X

A:

Q: 100 mm 100 mm 10 mm 10 mm. 200 mm 100 mm f 10 mm I II

A: For the selection of sections, we have to calculate the maximum bending stress in the beam. From the…

Q: G. A line 32 mm long joins to towns on a map of scale 1:100,000. (a) How far apart are the towns to…

A: For solution refer below images.

Q: 150 mm 50 mm 200 mm 50 mm 30 mm 200 mm -50 mm

A:

Q: Take a = 330 mm. y a - 70 mm 120 mm a

A:

Q: 200 mm В

A:

Q: 620 mm 125 350 mm

A: Consider the line diagram of the following figure as shown below – From the line diagram, it is…

Q: 300 mm 150 mm 150 mm 75 mm 100 mm 100 mm

A:

Q: 50 mm 150 mm 150 mm 300 mm *

A: A1=300×50A1=15000 mm2y¯1=3002=150 mm   from bottom,A2=300×50A2=15000 mm2y¯2=300+502=325 mm,

Q: 600 mm C 360mm

A:

Q: in 5 minutes please Diameter=38 L

A:

Q: 2 15 mm A 15 mm

A: Given : All the dimensions of the figure are given,  First calculate the initial length of diagonal…

Q: 250 mm

A: Given that, The force P=360 N,Q=480 N, The free-body diagram of the cable is as shown below,

Q: Locate the centroid of the plane area shown.

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: 100 mm 30 50 mm

A:

Q: y. what is the change in length in mm? k for =

A: Need to find change in length.

Q: 50 mm 150 mm 50 mm 85 mm Section X-X 20 kN

A: Let us shift the load to section X-X. The moment M and force P will create the same effect.

Q: Change following into SI units (MKS): (c) 2 hours

A: Change following into SI units (MKS):   (c) 2 hours

Q: 200 mm B 300 mm 400 mm 100 D G 600 mm

A:

Q: 2400 mm C 1200 mm 1200 mm 1200 mm 2400 mm

A: The free-body diagram of the plate is shown as, Given, m=102.1 kgW=102.1×9.81=1000.58 N

Q: C 110 mm F В 150 mm E 300 mm A D 200 mm 150 mm

A: There is a circumferential contact force between gears B and EF=TABrB=TEFrETEF=TABrErBTAB=170…

Q: S(10x¹ − 3x² +9)dx

A: GivenI=∫10x4-3x2+9dx

Q: 100 mm 25 mm 75 mm

A:

Q: 120 mm 600 mm 10-N 4N 600 mm 4N

A:

Q: aded (pink) arec 68 mm 68 mm 68 mm 68 mm 68 mm 68 mm 98740460 X mm4 mm4 mm mm

A:

Q: 4 kips/ft 1B 5 ft- 2 ft 2 ft 8 kins 8 kins

A: The loading diagram of the beam is shown as follows, Let's draw the free body diagram of the beam,

Q: D C 2 mm 5 mm

A: GivenAD=15mmAB=15mm

Q: 90 mm, 90 mm 170 mm 50 mm 37.5 mm Figure Q1 (a)

A: Find the maximum tensile stress and maximum compressive stress Moment=100KN-m

Moment of Inertia

Inertia can be termed as a resistance offered by a body to change its state. A rigid body initially at rest will apply resistance when acted by an external force that tends to change its state of rest or velocity, or a body initially at motion will provide resistance in changing its state of velocity or motion for coming to a state of rest. In other words, Newton's first law of motion describes the law of inertia of a rigid body.