A 150 mm B 240 mm 80 mm

Q: 200 mm 150 mm 100 mm 200 mm

A:

Q: A B 60° 3 kN 40° 2 kN

A:

Q: A 60 mm- В 90 mm- 100 mm C 4 kN 80 mm D 140 mm

A:

Q: mm. If nr

A:

Q: 80 mm 50 mm 2 1 7 15 mm 15 mm 3.

A: The Center of mass is a point where the sum of the moment of the weight of each particle is zero. It…

Q: X 300 mm D 800 mm B

A:

Q: y 200 mm 200 mm + 150 mm- 125 mm 60 mm 125 mm 1.

A:

Q: 150 200 mm D mm 150 150 v2 mm mm 0 = 45° E 12.5 rad/s

A: Given data,θ=45°ω=10 rad/sOB=1502mm=0.2155mAB=350mm=0.3556mO'A=150=0.1524m

Q: ust be from the origin. 70 mm mm 60 mm 10 mm

A: Area symbol area mm2 x̄(mm) ȳ (mm) A x̄(mm3) A ȳ (mm3) A1 40*15=600 -62.5 27.5 -37500…

Q: 90 mm 28 mm ·*-. -48 mm 48 mm -x

A: This is a basic problem of Engineering Mechanics. The concept of 2nd moment of area aka moment of…

Q: 100 mm 100 mm

A: GivenP=9kNd=6mm

Q: 40N 200 mm B

A: Given

Q: For the machine element shown, locate the z coordinate of the center of gravity.

A: Consider: Horizontal solid cuboid as 1 Vertical solid sem-cylinder as 2 Vertical cylindrical cavity…

Q: 1+154 mm 2-234 mm 3+114 mm B-15mm 28 kN |Yo

A: Given that, P=2.8 kNd=15 mm,b1=154 mm,b2=234 mm,b3=114 mm, For the given beam system the force…

Q: 200 N 250 N 630 mm 630 mm 630 mm

A: Total Distance = 630 +630+630 =1890 mmF1 = 200 NF2 = 250 NF3 = 355 N To-Determine:- Distance,d

Q: 25 mm R50mm 100 mm

A: Given

Q: m

A:

Q: Ix, Iy, Ixy 10 cm Y 5 cm 10 cm 5 cm X

A:

Q: Given: F = 40 N e = 20 deg a = 30 mm b = 200 mm

A:

Q: - 100 mm 20 mm yo 140 mm -20 mm 20 mm - 100 mm

A: Rectangle Area (mm2) x¯ (in) y¯ (in) x¯y¯A (in4) I 2000 -50 70 -7000000 II 2400 0 0 0 III 2000…

Q: 100 mm 100 mm 10 mm 10 mm. 200 mm 100 mm f 10 mm I II

A: For the selection of sections, we have to calculate the maximum bending stress in the beam. From the…

Q: For the machine element shown, locate the y coordinate of the center of gravity.

A: we have to determine the  y coordinate of center of gravity for the given machine element

Q: Take a = 330 mm. y a - 70 mm 120 mm a

A:

Q: F 1.0 1.0 cm cm 0.2 cm

A: The plate in the fluid medium subjected to not only  wall shear force but buoyant force also.  For a…

Q: 10 mm 20 mm 50 mm

A:

Q: y -9 cm- -3 cm 2 cm 19 cm 2 cm C 15 cm 9 cm- 3 cm→

A: Divide given figure in 3 section/shape,

Q: 52 mm, 28 mm- Figure Q1 (a) 2600 mm 620 mm

A:

Q: 6 mm 55 mm 10 mm

A: Impact loads are those loads that are acting for a short span of time. Toughness is defined as the…

Q: 500 sq mm в 300 sq mm 400 sq mm A D 10KN 40 KN 50 KN- 20 KN 200 mm 600 mm 300 mm

A: →For part AB:-Force, P=10kN=104NLength(L)=200mm, Area(A)=300mm2→For part BC:-Force,…

Q: 2 15 mm A 15 mm

A: Given : All the dimensions of the figure are given,  First calculate the initial length of diagonal…

Q: 9 cm cm S cm 7 cm

A: Answer- 5.9

Q: 300 mm 300 mm Figure Q2

A: Given data:- Area =1950 mm^2 Maximum deflection of point C = 0.6mm

Q: C 3 ft B 0.8 ft A

A:

Q: Locate the centroid of the plane area shown.

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: 300 N 36 mm

A: We need to apply force equlibirium equation along the horizontal direction∑Fx=0Ax-C=0......consider…

Q: y. what is the change in length in mm? k for =

A: Need to find change in length.

Q: -30 mm- 5 4 3 6. 80 mm 50 mm 2

A: The Center of mass is a point where the sum of the moment of the weight of each particle is zero. It…

Q: .1- Answer two of the following: a) What are deference between hot forming and cold fo

A: Hi and thanks for the question. Since you have asked multiple questions. As per the honour code, we…

Q: 45° B 10 in 10 in

A:

Q: y 1 in. 3 in. -3 in.-

A: Area of the triangle, A1=1/2(3)6=9in2 Area of the square, A2=3(3)=9 in2 Area of the quarter circle,…

Q: 60 500 mm o = 8 rad/s a = 16 rad/s 150 mm B 30

A:

Q: C 110 mm F В 150 mm E 300 mm A D 200 mm 150 mm

A: There is a circumferential contact force between gears B and EF=TABrB=TEFrETEF=TABrErBTAB=170…

Q: 7 panels at 4 m B C D 4 m A H. 8 kN 8 kN

A:

Q: F125 mm - 17 mm Yo +. -Xo 175 mm 17 mm 17 mm -125 mm- Answers: (10) mm4 i (106) mm4 i Iyo

A:

Q: 100 mm 25 mm 75 mm

A:

Q: B 200 mm 240 mm 60 30 KN igure (1.15)

A: First, make a FBD of the diagram as shown below,

Q: D C 2 mm 5 mm

A: GivenAD=15mmAB=15mm

Q: 90 mm, 90 mm 170 mm 50 mm 37.5 mm Figure Q1 (a)

A: Find the maximum tensile stress and maximum compressive stress Moment=100KN-m

Moment of Inertia

Inertia can be termed as a resistance offered by a body to change its state. A rigid body initially at rest will apply resistance when acted by an external force that tends to change its state of rest or velocity, or a body initially at motion will provide resistance in changing its state of velocity or motion for coming to a state of rest. In other words, Newton's first law of motion describes the law of inertia of a rigid body.