600 mm 600 mm

Q: 200 mm 150 mm 100 mm 200 mm

A:

Q: 9/16 inch is approximately equivalent to . mm. 19 17 14 12

A: The dial indicator is a traditional mechanical kind with a dial display that resembles a clock face…

Q: 80 mm 50 mm 2 1 7 15 mm 15 mm 3.

A: The Center of mass is a point where the sum of the moment of the weight of each particle is zero. It…

Q: X 300 mm D 800 mm B

A:

Q: y 200 mm 200 mm + 150 mm- 125 mm 60 mm 125 mm 1.

A:

Q: 1. 100 mm 225 mm 75 mm 125 mm 50 mm

A: According to the details provided in the question, we need to calculate centroid.

Q: 50 mm 30 mm 20 mm 40 mm * -60 mm- 40 mm x

A: GIVEN DATA- A COMPOSITE AREA GIVEN  WE HAVE TO FIND CENTROID OF AREA

Q: 30 mm 150 mm 30 mm 150 mm

A: given; →dimension for base block (b1*d1)=(150mm*30mm)→dimension for top block (b2*d2)=(30mm*150mm)

Q: Fx A 75 mm 50 mm 150 mm 350 mm В F2 250 mm y

A:

Q: 200 mm Gmm -4mm 400 8mm 102mm

A:

Q: 20° F = 10 N 250 mm 20N B 60% 37.5 mm

A: The given system of force is – The component of 10 N forces is –

Q: 48 mm

A:

Q: LA 5 mm 28 mm ー-ギー - 49 mm 49 mm

A: For triangle, X1= 0 Y1= (1/3)×95= 31.67 mm  A1 = 1/2 × 98× 95 = 4655 mm2 For semi circle, X2 =0 Y2=…

Q: 100 mm- 11.5 mm 7.5 mm N A 225 mm 11.5 mm (a)

A:

Q: Locate the centroid of the plane area shown.

A: The centroid of a 2d plane is the point at which the entire plane can be balanced on the tip of a…

Q: 1+154 mm 2-234 mm 3+114 mm B-15mm 28 kN |Yo

A: Given that, P=2.8 kNd=15 mm,b1=154 mm,b2=234 mm,b3=114 mm, For the given beam system the force…

Q: w = 35 kN/m 38-mm diameter 38-mm diameter 150-mm diameter 100 mm 300 mm 100 mm

A:

Q: 10 mm Y 15 mm 30 mm 40 mm 10 mm 15 mm X

A:

Q: Ix, Iy, Ixy 10 cm Y 5 cm 10 cm 5 cm X

A:

Q: - 100 mm 20 mm yo 140 mm -20 mm 20 mm - 100 mm

A: Rectangle Area (mm2) x¯ (in) y¯ (in) x¯y¯A (in4) I 2000 -50 70 -7000000 II 2400 0 0 0 III 2000…

Q: 100 mm 100 mm 10 mm 10 mm. 200 mm 100 mm f 10 mm I II

A: For the selection of sections, we have to calculate the maximum bending stress in the beam. From the…

Q: 150 mm 50 mm 200 mm 50 mm 30 mm 200 mm -50 mm

A:

Q: 30 mm OF 10 mm 30 mm 10 mm X

A: Option C is correct 503675.34 mm4

Q: Take a = 330 mm. y a - 70 mm 120 mm a

A:

Q: 200 mm В

A:

Q: 10 mm 20 mm 50 mm

A:

Q: 620 mm 125 350 mm

A: Consider the line diagram of the following figure as shown below – From the line diagram, it is…

Q: 300 mm 150 mm 150 mm 75 mm 100 mm 100 mm

A:

Q: 250mm 250mm Reinforcing Bars

A:

Q: Y. 20 mm 20 mm 260 mm 20 mm 200 mm

A:

Q: 500 sq mm в 300 sq mm 400 sq mm A D 10KN 40 KN 50 KN- 20 KN 200 mm 600 mm 300 mm

A: →For part AB:-Force, P=10kN=104NLength(L)=200mm, Area(A)=300mm2→For part BC:-Force,…

Q: 2 15 mm A 15 mm

A: Given : All the dimensions of the figure are given,  First calculate the initial length of diagonal…

Q: 250 mm

A: Given that, The force P=360 N,Q=480 N, The free-body diagram of the cable is as shown below,

Q: 9 cm cm S cm 7 cm

A: Answer- 5.9

Q: 300 mm 300 mm Figure Q2

A: Given data:- Area =1950 mm^2 Maximum deflection of point C = 0.6mm

Q: 50 N 100 mm 200 mm

A: As per our guidelines, experts can provide solution to only one problem in case of multiple…

Q: Locate the centroid of the plane area shown.

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: F=20 lb a Q6 25 mm 70 mm 100 mm- 70 25 mm mm

A:

Q: determine the minimum preferred size diameter.

A: Given: FOS=3  T2=0.15T2 To determine: The minimum diameter using distortion energy theory

Q: 300 N 36 mm

A: We need to apply force equlibirium equation along the horizontal direction∑Fx=0Ax-C=0......consider…

Q: 200 mm B 300 mm 400 mm 100 D G 600 mm

A:

Q: 2400 mm C 1200 mm 1200 mm 1200 mm 2400 mm

A: The free-body diagram of the plate is shown as, Given, m=102.1 kgW=102.1×9.81=1000.58 N

Q: F125 mm - 17 mm Yo +. -Xo 175 mm 17 mm 17 mm -125 mm- Answers: (10) mm4 i (106) mm4 i Iyo

A:

Q: Calculate the diameter e

A: Need to find diameter of Jet.

Q: 4. Mm

A: The moment of inertia of the rectangular section can be determined as,

Moment of Inertia

Inertia can be termed as a resistance offered by a body to change its state. A rigid body initially at rest will apply resistance when acted by an external force that tends to change its state of rest or velocity, or a body initially at motion will provide resistance in changing its state of velocity or motion for coming to a state of rest. In other words, Newton's first law of motion describes the law of inertia of a rigid body.