300 560 4 444 5 470 6 320 Identify the critical value(s) of the test statistic. Assume a two-tailed a = 0.05. (round to 2 decimal places) 2 3 Answer: 312 558 480 490 325
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- In a study to determine if the nitrogen content of the soil in Wyoming is less than the nitrogen content of the soil in North Dakota, 27 independent random soil samples from Wyoming and 32 from North Dakota were taken. Given the testing statistics below, determine if the data provides sufficient evidence to conclude that the nitrogen content of the soil in Wyoming is less than the nitrogen content of the soil in North Dakota, at the 1% significance level. H0:μw≥μnHa:μw<μn The test statistic is t0=−1.53 t0.01=−2.663Three samples of each of three types of PVC pipe of equal wall thickness are tested to failure under three temperature conditions, yielding the results shown below. Research questions: Is mean burst strength affected by temperature and/or by pipe type? Is there a “best” brand of PVC pipe? Burst Strength of PVC Pipes (psi) Temperature PVC1 PVC2 PVC3 Hot (70º C) 247 299 239 277 287 262 283 275 279 Warm (40º C) 325 341 297 322 319 315 296 335 304 Cool (10º C) 358 375 327 366 352 334 338 359 340 Click here for the Excel Data File (a-1) Choose the correct row-effect hypotheses. a. H0: A1 ≠ A2 ≠ A3 ≠ 0 ⇐⇐ Temperature means differ H1: All the Aj are equal to zero ⇐⇐ Temperature means are the same b. H0: A1 = A2 = A3 = 0 ⇐⇐ Temperature means are the same H1: Not all the Aj are equal to zero ⇐⇐ Temperature means differ a b (a-2) Choose the correct column-effect hypotheses. a. H0: B1 ≠ B2 ≠ B3 ≠ 0 ⇐⇐…In a study to determine if the nitrogen content of the soil in Wyoming is significantly different from the nitrogen content of the soil in North Dakota, 34 independent random soil samples from Wyoming and 36 from North Dakota were taken. Given the testing statistics below, determine if the data provides sufficient evidence to conclude that the nitrogen content of the soil in Wyoming is significantly different from the nitrogen content of the soil in North Dakota, at the 1% significance level. H0:μw=μnHa:μw≠μn The test statistic is t0=2.653 t0.005=±2.382
- Suppose the National Transportation Safety Board (NTSB) wants to examine the safety of compact cars, midsize cars, and full-size cars. It collects a sample of three for each of the treatments (cars types). Using the hypothetical data provided below, test whether the mean pressure applied to the driver’s head during a crash test is equal for each types of car. Use α = 5%. Compact Midsize Full-size 643 655 702 680 672 469 427 525 495 483 484 465 402 476 435 State the null and alternate hypothesis for the data. Given the results, what will be the conclusion of the team?The table below gives beverage preferences for random samples of teens and adults. Beverage Teens Adults Total Coffee 50 200 250 Tea 100 150 250 Soft drink 200 200 400 Other 50 50 100 400 600 1,000 With a .05 level of significance, the critical value for the test is _____.A simple random sample of front-seat occupants involved in car crashes is obtained. Among3000occupants not wearing seat belts,36were killed. Among 7697occupants wearing seat belts,18were killed. Use a0.05significance level to test the claim that seat belts are effective in reducing fatalities. Complete parts (a) through (c) below.
- In a study conducted to investigate browsing activity by shoppers, each shopper was initially classified as a nonbrowser, light browser, or heavy browser. For each shopper, the study obtained a measure to determine how comfortable the shopper was in a store. Higher scores indicated greater comfort. Suppose the following data were collected. Light Heavy Nonbrowser Browser Browser 10 9 7 11 10 9 12 9 7 9 8 9 9 11 6 10 8 8 11 10 7 10 9 9 . Use to test for a difference among mean comfort scores for the three types of browsers. Compute the values identified below (to 2 decimals, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error Calculate the value of the test statistic (to 2 decimals, if necessary). The -value is - Select your answer -less than .01between .01 and .025between .025 and .05between .05 and .10greater than .10Item 6 What is your…Three experiments investigating the relation between need for cognitive closure and persuasion were reported in “Motivated Resistance and Openness to Persuasion in the Presence or Absence of Prior Information,” by A. W. Kruglanski (Journal of Personality and Social Psychology, Vol. 65, No. 5, pp. 861–874). Part of the study involved administering a “need for closure scale” to a group of students enrolled in an introductory psychology course. The “need for closure scale” has scores ranging from 101 to 201. For the 73 students in the highest quartile of the distribution, the mean score was 178.70 . Assume a population standard deviation of 7.81. These students were all classified as high on their need for closure. Assume that the 73 students represent a random sample of all students who are classified as high on their need for closure. Find a 95% confidence interval for the population mean score on the “need for closure scale” for all students with a high need for closureIn one study of smokers who tried to quit smoking with nicotine path therapy,38 were smoking one year after the treatment, and 32 were not smoking one year after the treatment. Use a 0.10 significance level to test the claim that among smokers who try to quit with nicotine patch therapy, the majority are smoking a year after the treatment. d. Calculate the test statistic z. Which of these options is closest to z? A. negative 2.02 B. 0.72 C. negative 0.25 D. 2.59 e. Calculate the P-value. Which of these options is closest to the P-value? A. 0.2358 B. 0.2164 C. 0.3359 D. 0.2271 f. State the technical conclusion A. Reject Upper H 0 B. Do not reject Upper H 0 g. State the final conclusion A. There is sufficient evidence to warrant rejection of the claim. B. There is not sufficient evidence to warrant rejection of the claim.…
- A random sample of Engineering and Architecture students of a university were interviewed to determine if there is an association between study habits and academic performance. The results were tabulated below. Students Favourable Neutral Unfavourable Engineering 80 60 70 Architecture 100 50 70 Test the hypothesis that there is no significant difference between the study habits and academic performance using a 0.05 level of significance.Based on a survey of a random sample of 900 adults in the United States, a journalist reports that A random sample of 100 movie goers was asked to state his or her gender and favorite soft drink available at the local movie theater. The results appear in the table below. Is there a relationship between gender and soft drink preference? Coke Diet Coke Sprite Male 23 11 12 Female 16 28 10 To analyze the results, which of the following tests is most appropriate? A)Chi-square test of independence B)Chi-square test of homogeneity C)Two sample t-test D)Matched pair t-test E)Chi-square goodness of fit