33. Which of the following structures is composed of 12-20 carbon chains with carboxylic acid? Group of answer choices glycerol fatty acid alcohol steroid
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- _______ groups are the acid part of amino acids and fatty acids. a. Hydroxyl (OH) b. Carboxyl (COOH) c. Methyl (CH3) d. Phosphate (PO4)Which of the following is not a functional group that can bond with carbon? sodium hydroxyl phosphate carbonyl1. a. Explain why the melting point of palmitic acid (16 carbons, no double bonds) is slightly lower thanthat of stearic acid (18 carbons, no double bonds). Explain why the melting point of oleic acid (18carbons, one double bond) is lower than that of stearic acid b. A mixture of lipids containing phosphatidic acid, cholesterol, testosterone, phosphatidylserine, andphosphatidylethanolamine was applied to a hydrophobic interaction chromatography column. Thecolumn was washed with a high salt buffer, and the lipids were then eluted with decreasing saltconcentrations. In what order would the lipids be eluted from the column? Explain your answer.
- 1. Draw a circle around and give the name of each functional group in the following twomolecules. (Note: each line represents a covalent bond. If no atom is shown, assume there’s a carbon there.)3b) Both cysteine and methionine have sulfer in their side groups, but only cysteine side groups for disulfide bonds. Why don't methionine side groups also form covalent bonds with each other (or with a cysteine side group)?29-All of the following are examples of omega-3 fatty acids except: a.linoleic acid. b.linolenic acid. c.EPA. d.DHA.
- 6.All of the following types of interactions cooperate in stabilizing the tertiary structures of globular proteins except____. a.Disulphide bond b.Hydrogen bond c.Ionic interactions d.Peptide bond1. Methionine is an amino acid that contains a ___. *a. sodium atomb. sulfur atomc. phenyl ringd. heterocyclic ringe. chlorine atom 2. Which of the following shows all of the tripeptides that can be formed from one molecule each of glycine (Gly), valine (Val), and leucine (Leu)? *a. Gly-Val-Leu, Gly-Leu-Val, Leu-Gly-Valb. Val-Gly-Leu, Gly-Val-Leu, Gly-Leu-Val, Leu-Gly-Valc. Gly-Val-Leu, Gly-Leu-Val, Val-Leu-Gly, Val-Gly-Leu, Leu-Gly-Val, Leu-Val-Glyd. Val-Gly-Leu, Gly-Leu-Vale. Gly-Val-Leu 3. Two amino groups are present in ___. *a. leucineb. Lysinec. Glutamic acidd. threonine12. The sugars glucose, fructose, and inositol all have the same formula i.e. C6H12O6 yet they have 3 very similar but different structures. This is an example of: a) geometric isomers b) structural isomers c) stereo isomers d) none are correct
- 1. Construct the two enantiomeric forms/structure of the following monosaccharides and designate the handedness of each using D, L system 1. Ribulose18. D-galactose is soluble in water because of the interaction of the –OH groups of the monosaccharide and watermolecules. What type of intermolecular bond is established between the sugar and water?A. London Dispersion forcesB. Covalent bondC. Hydrogen bondD. Ion-dipole interaction 19. Some disaccharides are non-reducing because they have no free anomeric carbons. Based on this information, whichof the following disaccharides is non-reducing?A. glucopyranosyl α-(1 →4) glucopyranosideB. galactopyranosyl β-(1 → 4) glucopyranosideC. glucopyranosyl α-(1 → 2) fructopyranosideD. glucopyranosyl β-(1 → 3) glucopyranoside. 74. which of the following characteristics unifies all molecules that are considered to be lipids? they all have affinity for water due to the presence of carbonyl groups they all have little to no affinity for water due to the presence of hydrocarbons they all have little to no affinity for water due to the presence of carbonyl groups they all have affinity for water due to the presence of hydrocarbons