3876741091676 quany? Jump to level 1 In a poll of 1000 randomly selected voters ina local election, 272 voters were against school bond measures. What is the sample proportion ? Ex 0,123 E What is the margin of error m for the 95% confidence level? Ex 0.123
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- A large automobile insurance company selected samples of single and married male policy-holders and recorded the number who made an insurance claim over the preeding three-year period. Male Policy Holders: Single Married Sample size 400 900 No. Making claims 76 90 Conduct a hypothesis test to determine whether there is a difference in proportion of claims between single and married male policy holders. Use a 0.05 level of significance Provide a 95% confidence interval for the difference between the proportions for the two populations. Suppose now that we also have data on the number of claims by male retirees. The data are now: Male policy holders: Single Married Retirees No. Making claims 76 90 45 Sample size 400 900 250 Assume that the three categories are mutually exclusive. Using a 0.05 significance level and a critical value approach, conduct an appropriate test to determine if there is a significant…Construct a 90% confidence interval for μ1−μ2 with the sample statistics for mean cholesterol content of a hamburger from two fast food chains and confidence interval construction formula below. Assume the populations are approximately normal with unequal variances.This chart shows the results of two random samples that measured the average number of minutes per charge for AA Lithium-ion (Li-ion) rechargeable batteries versus Nickel-Metal Hydride (NiMH) rechargeable batteries. Down below shows the hypothesis test using significance level (α) = 0.05 to determine if the true average number of minutes per charge for NiMH batteries is smaller than that for Li-ion batteries. 1. From the data given from the first graph below, what would be the correct p value? (the one tail or the two tail?) t-Test: Two-Sample Assuming Unequal Variances NiMH Li-ion Mean 89.35714 95 Variance 3.93956 59.75 Observations 14 17 Hypothesized Mean Difference 0 df 19 t Stat -2.89621 P(T<=t) one-tail 0.004628 t Critical one-tail 1.729133 P(T<=t) two-tail 0.009255 t Critical two-tail 2.093024 For the bottom graph: 1.. Find the point estimate (you can do this by subtracting Group 2…
- Some manufacturers claim that non-hybrid sedan cars have a lower mean miles-per-gallon (mpg) than hybrid ones. Suppose that consumers test 254 hybrid sedans and get a mean of 26 mpg with a standard deviation of 4 mpg. Also, 237 non-hybrid sedans get a mean of 24 mpg with a standard deviation of 6 mpg. Suppose that both populations are known to be normal distributed. Conduct a hypothesis test to evaluate the manufacturers' claim. Test at a 4% level of significance. Let population 1 denote non-hybrids and population 2 denote hybrids. (a) H0 : μ1 ______ μ2 (b) Ha : μ1 _______ μ2 (c) In words, state what your random variable represents.The random variable is the (mean / difference in the / difference in the mean) miles per gallon of non-hybrid sedans and hybrid sedans.a. interpret the corresponding 95% confidence intervals for both Birth weight and Age. b. What is the predicted average SBP of an infant born with birth weight 8lbs (128oz) measured at 3 days old? c. Calculate the Pearson correlation between Age and Birth weight, and test if this correlation is significant at the 0.05 level. Does this answer surprise you, why or why not?Assume that last year in a particular state there were 211 children out of 1990 who were diagnosed with Autism Spectrum Disorder. Nationally, 1 out of 88 children are diagnosed with ASD. It is believed that the incident of ASD is more common in that state than nationally. Calculate a 96% confidence interval for the percentage of children in that state diagnosed with ASD.P: Parameter What is the correct parameter symbol for this problem? What is the wording of the parameter in the context of this problem? A: Assumptions Since information was collected from each object, what conditions do we need to check? Check all that apply. n≥30n≥30 or normal population. N≥20nN≥20n n(pˆ)≥10n(p̂)≥10 σσ is known. σσ is unknown. n(1−pˆ)≥10n(1-p̂)≥10 Check those assumptions: 1. nˆpnp^= which is 2. n(1−ˆp)n(1-p^)= which is 3. NN= which is If no N is given in the problem, use 1000000N: Name the procedure The…
- A sample of size 25 drawn from a normally distributed population has a sample mean 12 and a sample standard deviation 5. Construct an 80% confidence interval for the population mean.From a stand of eucalyptus, 25 trees were drawn and their diameters were determined, in cm, in order to estimate the mean diameter of the stand. These diameters were: a) Based on this sample, calculate the 90% and 95% confidence intervals for the population mean.b) Obtain the 95% confidence interval for population variance.The article “Arsenic and Mercury in Lake Whitefish and Burbot Near the Abandoned Giant Mine on Great Slave Lake” (P. Cott, B. Zajdlik, et al., Journal of Great Lakes Research, 2016:223–232) presents measurements of arsenic concentrations in fish found in Northern Canada. a) In a sample of 8 whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a standard deviation of 0.05 mg/kg. Find a 95% confidence interval for the concentration in whitefish found in Yellowknife Bay. b) In a sample of 8 whitefish caught in Baker Pond, the mean arsenic concentration in the liver was 0.55 mg/kg, with a standard deviation of 0.36 mg/kg. Should the Student’s t distribution be used to find a 95% confidence interval for the concentration in whitefish found in Baker Pond? If so, find the confidence interval. If not, explain why not.
- A chemical plant is expected to have a mean daily production of at least 740 tons when it is properly operating. A quality control engineer has measured the output on a simple random sample of 60 days. The sample had a mean of 730 tons/day and a standard deviation of 24 tons/day. The engineer is required to judge whether the plant is producing as per expectations. (i). Write down the null and alternative hypothesis using correct symbols.. (iii). Show the rejection region graphically at 5% level.. (iv). Should the null hypothesis be rejected at 5% level? Based on your answer explain, whether the plant is operating properly..in 2015, average american male weight was 198 lbs. Experts want to know if this average has increased.A) What is the population and the population parameter for which inferencing is being done?B) Formulate the hypothesis that can be used to test this suspision that average weight has increasedC) a sample of 60 american males yielded average weight of 201.5 lbs with a STDEV of 16 lbs. What can be concluded at a 4% level of significance?D) Would conclusion change if significance were changed to 1%? why or why not