4) A redox titration: 20.00 mL of 0.00500 M Sn²+ solution below. Titration reaction: Bucony C Ce+ + e-------> Ce³+ Sn + 2e-> Sn²+ 0.00500 M Sa was titrated with 0.0200 M Ce according to the reactio Cod unce de P Magre 2 Ce+ + Sn²+> 2 Ce³+ + Sn¹+ Eº 1.470 V 0.139 V a) What is VE (the equivalence volume) (of Ce**) needed to reach the endpoint? b) Calculate the potential (voltage) relative to SCE, when 5.00 mL Ce+ is added. SCE = +0.241 V

Fundamentals Of Analytical Chemistry
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Chapter16: Applications Of Neutralization Titrations
Section: Chapter Questions
Problem 16.20QAP
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4) A redox titration: 20.00 mL of 0.00500 M Sn²+ solution was titrated with 0.0200 M Ce+*+ according to the reactio
below.
Titration reaction:
Burst coreaning Co
Ce4+ + e-------> Ce³+
Sn²+ + 2e ------> Sn²+
appy
0.00500 M Sn
Calomal
Pt wire
Magneto
stirring bar
2 Ce4+ + Sn²+ --> 2 Ce³+ + Sn¹+
Eº
1.470 V
0.139 V
a) What is VE (the equivalence volume) (of Ce4+) needed to reach the endpoint?
b) Calculate the potential (voltage) relative to SCE, when 5.00 mL Ce4+ is added.
SCE = +0.241 V
Transcribed Image Text:4) A redox titration: 20.00 mL of 0.00500 M Sn²+ solution was titrated with 0.0200 M Ce+*+ according to the reactio below. Titration reaction: Burst coreaning Co Ce4+ + e-------> Ce³+ Sn²+ + 2e ------> Sn²+ appy 0.00500 M Sn Calomal Pt wire Magneto stirring bar 2 Ce4+ + Sn²+ --> 2 Ce³+ + Sn¹+ Eº 1.470 V 0.139 V a) What is VE (the equivalence volume) (of Ce4+) needed to reach the endpoint? b) Calculate the potential (voltage) relative to SCE, when 5.00 mL Ce4+ is added. SCE = +0.241 V
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