4- An electron in an x-ray machine is accelerated through a potential difference of 5*104 V before it hits the target. The change in electric potential energy is: (e = 1.6*10-19 C)a) -8*10-15 Jb) 8*10-15 Jc) 5*10-13Jd) 9*10-12J 5- A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 3000 N/C. The change in the electric potential energy of the proton–field system when the proton travels to x =5 m is: (e = 1.6*10-19 C)a) 24*10-16Jb) -24*10-16 Jc) 5000 Jd) 1000 J

Question

4- An electron in an x-ray machine is accelerated through a potential difference of 5*104 V before it hits the target. The change in electric potential energy is: (e = 1.6*10-19 C)
a) -8*10-15 J
b) 8*10-15 J
c) 5*10-13J
d) 9*10-12J


5- A proton is released from rest at the origin in a uniform electric field in the positive x direction with magnitude 3000 N/C. The change in the electric potential energy of the proton–field system when the proton travels to x =5 m is: (e = 1.6*10-19 C)
a) 24*10-16J
b) -24*10-16 J
c) 5000 J
d) 1000 J

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