Question 4 4) Gaseous acetaldehyde CH₂CHO undergoes decompositionreaction where it was present at initial pressure P. = 363 Torr.The rate of its decomposition v was 1.07 Torr s¹ when 5.0 %had reacted,01and it was 0.76 Torr s¹ when 20.0 % had reacted.Determine the order of this reaction.Hint: start with generic formula v = k (P)".Then make a small Table with conversion rates, partialpressures, and reaction rates. Make the formula linear to thedesired power a.

Answered: 4) Gaseous acetaldehyde CH₂CHO…

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter11: Chemical Kinetics

Section: Chapter Questions

Problem 11.51PAE: 11.51 Peroxyacetyl nitrate (PAN) has the chemical formula CtHjNOj and is an important lung irritant...

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Question 4

4) Gaseous acetaldehyde CH₂CHO undergoes decomposition
reaction where it was present at initial pressure P. = 363 Torr.
The rate of its decomposition v was 1.07 Torr s¹ when 5.0 %
had reacted,
0
1
and it was 0.76 Torr s¹ when 20.0 % had reacted.
Determine the order of this reaction.
Hint: start with generic formula v = k (P)".
Then make a small Table with conversion rates, partial
pressures, and reaction rates. Make the formula linear to the
desired power a.

Expert Solution

Step 1

According to the reaction,

$T h e i n i t i a l p r e s s u r e o f t h e g a s e o u s a c e t a l d e h y d e i s g i v e n b y = P_{0} = 363 t o r r$

$\begin{array}{rcl} T h e r a t e o f d e c o m p o s i t i o n i s g i v e n b y, \\ v & = & k {(P_{A})}^{α} \end{array}$

where,

$\begin{array}{rcl} k & = & r a t e c o n s \tan t \\ P_{A} & = & P r e s s u r e a t g i v e n t i m e \\ α (a l p h a) & = & o r d e r o f r e a c t i o n \end{array}$

The two condition is also given,

$v_{1} = 1.07 t o r r w h e n 5.0 % r e a c t e d v_{2} = 0.76 t o r r w h e n 20.0 % r e a c t e d$

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