4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSO4 with a offer amount of Zn equal to 6 x 10 mol, the percentage yield of (Cu) according to the equation: CuSO(ag)+Zn(s) ZnSO. (aq) +Cu (s) a) 75% b) 83% c) 65% d) 90%.

Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter6: Types Of Chemical Reactions And Solution Stoichiometry
Section: Chapter Questions
Problem 132CP: Consider reacting copper(II) sulfate with iron. Two possible reactions can occur, as represented by...
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homework5 (Compatibility Mode]- Word (Product Activation Failed)
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4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSO
with a offer amount of Zn equal to 6 x 103 mol, the percentage yield of (Cu)
according to the equation :
CuSO.(ag)+Zn(s) ZnSO. (ag) +Cu (s)
a) 75%
b) 83%
c) 65%
d) 90%.
5) For the following reaction:
I (g) + H: (g) → 2HI (g)
If the amount consumed from (I) according to the above reaction is (50.8g) and the
actual yield of HI is (40g) then the percentage yield of (HI) is equal to :
a) 78.125%
b) 15.625%
c) 63.341%
d)39.06% .
6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH according
to the equation:
HNO. + LIOH → LINO, + HO
a) 46
) 29
c) 2
d) 11
31
hp
Transcribed Image Text:homework5 (Compatibility Mode]- Word (Product Activation Failed) ces Mailings Review View Tell me what you want to do. AaBbCcD AaBbCcDc AaBbC AaBbCcl Aa . A I Normal T No Spac.. Heading 1 Heading 2 Title Paragraph Styles 4) If the actual yield of Cu is the result of the reaction of 8 x 10 mol of CuSO with a offer amount of Zn equal to 6 x 103 mol, the percentage yield of (Cu) according to the equation : CuSO.(ag)+Zn(s) ZnSO. (ag) +Cu (s) a) 75% b) 83% c) 65% d) 90%. 5) For the following reaction: I (g) + H: (g) → 2HI (g) If the amount consumed from (I) according to the above reaction is (50.8g) and the actual yield of HI is (40g) then the percentage yield of (HI) is equal to : a) 78.125% b) 15.625% c) 63.341% d)39.06% . 6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH according to the equation: HNO. + LIOH → LINO, + HO a) 46 ) 29 c) 2 d) 11 31 hp
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a) 78.125%
d)39 06% -
b) 15.625%
c) 63.341%
6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH according
to the equation:
HNO, +LIOH → LINO, + H. O
a) 46
b) 29
c) 2
d) 11
7) The mass of potassium hydroxide (KOH) to be dissolved in (100 ml) of water to
obtain a solution of 0.25M concentration is:
a) 1.4g
b) 4.5g
c) 0.025g
d) 5.6g .
8) Molarity (5g) of NaOH dissolved in 120 ml of solution the molar is :
a) 0.75M
b) 1. 04M
c) 1.25M
d) 0.5M
9) How many grams of A1C1 should be dissolved, to prepare 1 liter of a solution
in which the concentration of Cl ions 0.6M?
a) 240.3 grams
b) 80.1 grams
c) 26.7 grams
d) 41.1 grams
10) For the following reaction:
2A + 3B - 2AB
Atomic a Weights A= 27 &B= 35.5
The number of grams of AB. consisting of (12g) interaction of B:
a) 26.2g
Molecular weight AB = 133.5 g mol
b) 15.04g
c) 20g
d) 31.4g
hp
Transcribed Image Text:AaBbCcDc AaBbCcDr AaBbC 前, I No Spac. Heading 1 TNormal Paragraph a) 78.125% d)39 06% - b) 15.625% c) 63.341% 6) The remaining mass of (92g) of HNO, if reacted with (24g) of LIOH according to the equation: HNO, +LIOH → LINO, + H. O a) 46 b) 29 c) 2 d) 11 7) The mass of potassium hydroxide (KOH) to be dissolved in (100 ml) of water to obtain a solution of 0.25M concentration is: a) 1.4g b) 4.5g c) 0.025g d) 5.6g . 8) Molarity (5g) of NaOH dissolved in 120 ml of solution the molar is : a) 0.75M b) 1. 04M c) 1.25M d) 0.5M 9) How many grams of A1C1 should be dissolved, to prepare 1 liter of a solution in which the concentration of Cl ions 0.6M? a) 240.3 grams b) 80.1 grams c) 26.7 grams d) 41.1 grams 10) For the following reaction: 2A + 3B - 2AB Atomic a Weights A= 27 &B= 35.5 The number of grams of AB. consisting of (12g) interaction of B: a) 26.2g Molecular weight AB = 133.5 g mol b) 15.04g c) 20g d) 31.4g hp
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