Consider the Haber-Bosch process for the synthesis of ammonia from its elements. Calculate the theoretical yield in moles NH: from the complete reaction of 59.8 grams N2 in the presence of excess H2 gas according to the following balanced chemical equation: N:(g) + 3 H:(g) - 2 NH:(g) 1 metN. 2 mol NH, 59.8 4.27 mol NH: STARTING AMOUNT 28.02 3 metNE 1 mol N2 2 mol NH, 59.8 g N2 x = 4.27 mol NH. 28.02 g N2 3 mol N2 ADD FACTOR DELETE ANSWER RESET *( ) 7.04 17.04 3 2.13 3.52 1.01 59.8 14.01 28.02 4.27 g/mol N2 g/mol NH. g NH, g N2 mol NH. mol N2

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Chapter6: Chemical Reactions: An Introduction
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Consider the Haber-Bosch process for the synthesis of ammonia from its elements.
Calculate the theoretical yield in moles NH: from the complete reaction of 59.8
grams N2 in the presence of excess H2 gas according to the following balanced
chemical equation:
N:(g) +
H:(g) –
2
NH:(g)
1
metN:
mol NH3
59.8
4.27
mol NH3
STARTING AMOUNT
28.02
3
metN.
1 mol N2
2 mol NH3
59.8 g N2 x
= 4.27 mol NH3
28.02 g N2
3 mol N2
ADD FACTOR
DELETE
ANSWER
RESET
*( )
7.04
17.04
3
2.13
3.52
1.01
59.8
1
14.01
28.02
4.27
g/mol N2
g/mol NH3
g NH3
g N2
mol NH3
mol N2
2.
2.
Transcribed Image Text:Consider the Haber-Bosch process for the synthesis of ammonia from its elements. Calculate the theoretical yield in moles NH: from the complete reaction of 59.8 grams N2 in the presence of excess H2 gas according to the following balanced chemical equation: N:(g) + H:(g) – 2 NH:(g) 1 metN: mol NH3 59.8 4.27 mol NH3 STARTING AMOUNT 28.02 3 metN. 1 mol N2 2 mol NH3 59.8 g N2 x = 4.27 mol NH3 28.02 g N2 3 mol N2 ADD FACTOR DELETE ANSWER RESET *( ) 7.04 17.04 3 2.13 3.52 1.01 59.8 1 14.01 28.02 4.27 g/mol N2 g/mol NH3 g NH3 g N2 mol NH3 mol N2 2. 2.
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