4) Nicotine, the stimulant in tobacco, causes a very complex set of physiological effects in the body. It is composed of carbon, hydrogen, and nitrogen, and has a molar mass of 162 g/mol. When a 0.395 g sample of nicotine was burned, 1.072 g of carbon dioxide, 0.307 g of water, and 0.068 g of nitrogen gas were produced. What are the empirical and molecular formulas of nicotine? Write the balanced equation for the combustion of nicotine.
4) Nicotine, the stimulant in tobacco, causes a very complex set of physiological effects in the body. It is composed of carbon, hydrogen, and nitrogen, and has a molar mass of 162 g/mol. When a 0.395 g sample of nicotine was burned, 1.072 g of carbon dioxide, 0.307 g of water, and 0.068 g of nitrogen gas were produced. What are the empirical and molecular formulas of nicotine? Write the balanced equation for the combustion of nicotine.
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter3: Calculations With Chemical Formulas And Equaitons
Section: Chapter Questions
Problem 3.131QP
Related questions
Question
Transcribed Image Text:4) Nicotine, the stimulant in tobacco, causes a very complex set of physiological effects in the
body. It is composed of carbon, hydrogen, and nitrogen, and has a molar mass of 162 g/mol.
When a 0.395 g sample of nicotine was burned, 1.072 g of carbon dioxide, 0.307 g of water,
and 0.068 g of nitrogen gas were produced. What are the empirical and molecular formulas of
nicotine? Write the balanced equation for the combustion of nicotine.
Balanced Combustion Equation
Expert Solution
Step 1
From the amount of CO2, H2O and N2 formed, we find out the amount of C, N and H present in the given nicotine sample.
Empirical formula - C5H7N
Molecular formula - C10N2H14
Balanced combustion equation -
2 C10H14N2 + 17 O2 = 20 CO2
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
General Chemistry - Standalone book (MindTap Cour…
Chemistry
ISBN:
9781305580343
Author:
Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
General Chemistry - Standalone book (MindTap Cour…
Chemistry
ISBN:
9781305580343
Author:
Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning