   Chapter 2, Problem 155GQ

Chapter
Section
Textbook Problem

A piece of nickel foil, 0.550 mm thick and 1.25 cm square, is allowed to react with fluorine, F2, to give a nickel fluoride.(a) How many moles of nickel foil were used? (The density of nickel is 8.902 g/cm3.)(b) If you isolate 1.261 g of the nickel fluoride, what is its formula?(c) What is its complete name?

(a)

Interpretation Introduction

Interpretation: The moles of nickel foil in a piece of nickel foil with thickness of 0.550mm and 1.25cm square that reacted with fluorine should be calculated.

Concept introduction:

Conversion formula for mass of a molecule and number moles,

Numberofmoles=MassingramsMolarmass

Equation for mass from volume and density is,

Density×Volume=Mass

Ionic compounds are formed by the combination of metal and nonmetals or metal and polyatomic ions. Metals have the positive charge (cation) and counterpart has the negative charge (anion).

Formula of a compound is the representation of atoms or polyatoms present in the compound by their respective symbol.

• Naming of ions:

Positive ions (cations) are named as metal name, example: aluminum for aluminum cation.

But, for the transition metals the ionic charge also included by roman numerals with the naming of compound.

Negative ions (anions) are named by adding ‘ide’ to the stem of the nonmetal element, from which the anion is formed, example: chloride, bromide, etc.

Explanation

The thickness of the nickel foil is given that 0.550mm=0.055cm and 1.25cm square.

Therefore, the volume of the nickel foil is,

0.055cm×1.25cm×1.25cm=0.086cm3

The density of the nickel is given as 8.902g/cm3.

Equation for mass from volume and density is,

Density×Volume=Mass

Therefore, the mass of nickel foil is,

8.902g/cm3×0.086cm3=0

(b)

Interpretation Introduction

Interpretation: The formula for isolated 1.261g of nickel fluoride should be identified.

Concept introduction:

Conversion formula for mass of a molecule and number moles,

Numberofmoles=MassingramsMolarmass

Equation for mass from volume and density is,

Density×Volume=Mass

Ionic compounds are formed by the combination of metal and nonmetals or metal and polyatomic ions. Metals have the positive charge (cation) and counterpart has the negative charge (anion).

Formula of a compound is the representation of atoms or polyatoms present in the compound by their respective symbol.

• Naming of ions:

Positive ions (cations) are named as metal name, example: aluminum for aluminum cation.

But, for the transition metals the ionic charge also included by roman numerals with the naming of compound.

Negative ions (anions) are named by adding ‘ide’ to the stem of the nonmetal element, from which the anion is formed, example: chloride, bromide, etc.

(c)

Interpretation Introduction

Interpretation: The complete name should be identified.

Concept introduction:

Conversion formula for mass of a molecule and number moles,

Numberofmoles=MassingramsMolarmass

Equation for mass from volume and density is,

Density×Volume=Mass

Ionic compounds are formed by the combination of metal and nonmetals or metal and polyatomic ions. Metals have the positive charge (cation) and counterpart has the negative charge (anion).

Formula of a compound is the representation of atoms or polyatoms present in the compound by their respective symbol.

• Naming of ions:

Positive ions (cations) are named as metal name, example: aluminum for aluminum cation.

But, for the transition metals the ionic charge also included by roman numerals with the naming of compound.

Negative ions (anions) are named by adding ‘ide’ to the stem of the nonmetal element, from which the anion is formed, example: chloride, bromide, etc.

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started 