*•4 The angular position of a point on the rim of a rotating wheel is given by 0= 4.0t-3.012 +, where e is in radians and t is in seconds. What are the angular velocities at (a) t = 2.0 s and (b) t = 4.0 s? (c) What is the average angular accel- eration for the time interval that begins at t 2.0 s and ends at t = 4.0 s? What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval? Solution

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotational Motion
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4 The angular position of a point on the rim of a rotating
wheel is given by e = 4.01 – 3.0² + t², where 6 is in radians
and t is in seconds. What are the angular velocities at (a) t =
2.0 s and (b) 1 = 4.0 s? (c) What is the average angular accel-
eration for the time interval that begins at t 2.0 s and ends
at t = 4.0 s? What are the instantaneous angular accelerations
at (d) the beginning and (e) the end of this time interval?
-
Solution
Transcribed Image Text:4 The angular position of a point on the rim of a rotating wheel is given by e = 4.01 – 3.0² + t², where 6 is in radians and t is in seconds. What are the angular velocities at (a) t = 2.0 s and (b) 1 = 4.0 s? (c) What is the average angular accel- eration for the time interval that begins at t 2.0 s and ends at t = 4.0 s? What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval? - Solution
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