4 z+9 (z – 2) + 2 (9 – 2) < 18 (x + 1) Enter the exact answer in interval notation. -To enter 00, type infinity.

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A: Since you have asked multiple question, we will solve the first question for you. If youwant any…

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A: f(x) = x4 + x - 6 ƒ is continuous over the closed interval [a, b] if and only if it's continuous on…

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Q: 19. The interval for function |(3 )/2 z-1|<2 is -2/3 ,21 (- 2/3 ,2) (-2/3 ,2] - 2/3 ,2)

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A: Given IVP is x''=-6x(x')3 , x(-1)=-1 ,x'(-1)=13

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A: To expand and simplify the given terms in the ascending powers.   Expression In the power of:…

Q: 10+ Concave up on the intervalcs): Concauc down on the intervalcsso 4- 6 There is an in flection…

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Q: find the interval of existence in which the particular solutions of the IVP is vaild

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Q: Use the Intermediate Value Theorem to show that there is a root of the given equation in the…

A: The given equation is x4-x-8=0. Intermediate Value Theorem: Let f be a continuous function on the…

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Q: 14) Use the Intermediate Value Theorem to show that the po zero in the given interval. g(x) = 2x³ –…

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Q: 6. Show that the half open interval [0, 2) is uncountable. (Hint: We know that (0, 2) is uncount-…

A: Since the interval (0, 2) contains the infinite subset {1.2,1.3,1.4,...} So (0, 2) is either…

Q: 1) Find the absolute extremum values of f(x)=x2-4x+20f(x)%3DX2-4x+20 over the interval [1,4][1,4].

A: The extrema value of  function is f(4)=20

Q: nsider the following equation. 3x4 - 8x3 + 2 = 0, [2, 3] (a) Explain how we know that the given…

A: Given: 3x4-8x3+2=0, x∈2,3 we know that if any functionfx is continuous on intervala,b and fa&lt;0,…

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Q: Use the Intermediate Value Theorem to show that there is a root of the given equation in the…

A: Since x^4+x-8 is a polynomial it is continuous.Answer: f(x)=x^4+x-8 is continuous on the closed…

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A: The given data is: Prove that fx=4x-22x has at least one real zero in the interval 1,2 without…

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A: The given initial value problem is, x''=-6x(x')3                                     ..............1…

Q: - Give the domain for k(a) in interval notation. x2 + 3x +2

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Q: on is discontinuous on the specified interval. Vx2 - 64 if IS -8 if-8<x<8 88] 0 ifx28 f(x) = {x+8

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Q: 4) Consider the function fex)= Slx-s] Evaluate 7-4 for any There is no solution to the equati on…

A: Given: fx=5x-5 so, f7-f47-4=57-5-54-57-4=52-13=513=53

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A: Given that: f(x)=3x+1x-3