4. A 0.1475-M solution of Ba(OH)2 was used to titrate the acetic acid (60.05 g/mol) in a dilute aqueous solution. The following results were obtained. Sample Sample Volume, mL Ba(OH), Volume, mL 1 50.00 43.17 49.50 42.68 21.47 3 4 25.00 50.00 43.33 2CH;COOH + Ba(OH)2 → Ba(CH3C00) + 2H2O (a) Calculate the mean w/v percentage of acetic acid in the sample.

Fundamentals Of Analytical Chemistry
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Chapter16: Applications Of Neutralization Titrations
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Problem 16.20QAP
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4. A 0.1475-M solution of Ba(OH)2 was used to titrate the acetic acid (60.05 g/mol) in a dilute aqueous
solution. The following results were obtained.
Sample Sample Volume, mL Ba(OH), Volume, mL
1
50.00
43.17
49.50
42.68
3
21.47
25.00
50.00
4
43.33
2CH3COOH + Ba(OH)2 → Ba(CH;CO0), + 2H2O
(a) Calculate the mean w/v percentage of acetic acid in the sample.
Transcribed Image Text:4. A 0.1475-M solution of Ba(OH)2 was used to titrate the acetic acid (60.05 g/mol) in a dilute aqueous solution. The following results were obtained. Sample Sample Volume, mL Ba(OH), Volume, mL 1 50.00 43.17 49.50 42.68 3 21.47 25.00 50.00 4 43.33 2CH3COOH + Ba(OH)2 → Ba(CH;CO0), + 2H2O (a) Calculate the mean w/v percentage of acetic acid in the sample.
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