4. Two blocks, A (mass=5.00 kg)and B (mass= 10.0 kg) aresuspended by a cord on eitherside of a pulley. (Ignore massand friction of pulley, the corddoes not stretch, so accelerationis the same for both blocks.Find the acceleration (m/s^2) ofthe blocks; 10.0 kg block goesdown while 5.00 kg block goes up5 kg10 kg 1. A woman stands on aweighing scale in a non - movingelevator. When the elevatorstarted to move, the scalemomentarily reads only 0.60 ofthe person's normal weight. Findacceleration (m/s^2)2. A 2500. kg Toyota car traveled20. Meter and then stopped tofill up the car with gasoline.Initial speed is 10.m /s. Find theamount of force needed inNewton to allow it to stop.3. The figure shows a 100.kgbox suspended from the extremeside of the horizontal truss.Assume that the truss's weightis negligible; what is the tension(N) in the cord supporting thetruss. Angle is 38 degrees fromthe horizontal side of the trussCOADtruss100kg

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4. Two blocks, A (mass=5.00 kg) and B (mass= 10.0 kg) are suspended by a cord on either side of a pulley. (Ignore mass and friction of pulley, the cord does not stretch, so acceleration is the same for both blocks. Find the acceleration (m/s^2) of the blocks; 10.0 kg block goes down while 5.00 kg block goes up 5 kg 10 kg

4. Two blocks, A (mass=5.00 kg) and B (mass= 10.0 kg) are suspended by a cord on either side of a pulley. (Ignore mass and friction of pulley, the cord does not stretch, so acceleration is the same for both blocks. Find the acceleration (m/s^2) of the blocks; 10.0 kg block goes down while 5.00 kg block goes up 5 kg 10 kg

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter5: Newton's Law Of Motion

Section: Chapter Questions

Problem 27P: Astronauts in orbit are apparently weightless. This means that a clever method of measuring the mass...

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