1. Calculate the magnitude of the impulse during the collision.2. Calculate the magnitude and direction of the velocity of the 4.0 kg cart after the collision.3. Calculate the mass m of the second cart 4.0 m/s3.0 kgA 3.0 kg cart is moving at a speed of 4.0 m/s to the right across africtionless table, as shown above. It collides with a second cart ofan unknown mass m that is initially at rest. The magnitude of theforce Fof the collision as a function of time tis shown in thegraph below, where t= 0 is the instant of initial contact. As aresult of the collision, the second cart acquires a speed of 1.6 m/sto the right. Assume that friction is negligible before, during, andafter the collision.10Force (N)51.02.0Time (s)

mass of first cart (M) = 3 kg Initial speed of cart (v) = 4 ms (towards right)Force versus time…

Answered: 4.0 m/s 3.0 kR A 3.0 kg cart is moving…

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter9: Linear Momentum And Collisions

Section: Chapter Questions

Problem 9.4OQ: A 2-kg object moving to the right with a speed of 4 m/s makes a head-on, elastic collision with a...

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Question

1. Calculate the magnitude of the impulse during the collision.

2. Calculate the magnitude and direction of the velocity of the 4.0 kg cart after the collision.

3. Calculate the mass m of the second cart

4.0 m/s
3.0 kg
A 3.0 kg cart is moving at a speed of 4.0 m/s to the right across a
frictionless table, as shown above. It collides with a second cart of
an unknown mass m that is initially at rest. The magnitude of the
force Fof the collision as a function of time tis shown in the
graph below, where t= 0 is the instant of initial contact. As a
result of the collision, the second cart acquires a speed of 1.6 m/s
to the right. Assume that friction is negligible before, during, and
after the collision.
10
Force (N)
5
1.0
2.0
Time (s)

Expert Solution

Step 1

$mass of first cart (M) = 3 k g Initial speed of cart (v) = 4 \frac{m}{s} (t o w a r d s r i g h t) Force versus time graph is provided which has a maximum force of 10 N. Initial speed of second cart = 0 \frac{m}{s} Mass of second cart = m Final speed of second cart = 1.6 \frac{m}{s}$

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