4.4 • A man is dragging a trunk up the loading ramp of a mover's truck. The ramp has a slope angle of 20.0°, and the man pulls upward with a force F whose direction makes an angle of 30.0° with the ramp (Fig. E4.4). (a) How large a force F is necessary for the component F, parallel to the ramp to be 90.0 N? (b) How large will the component F, perpendicular to the ramp be then?

Principles of Physics: A Calculus-Based Text
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Chapter5: More Applications Of Newton’s Laws
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4.4 • A man is dragging a trunk up the
loading ramp of a mover's truck. The
ramp has a slope angle of 20.0°, and
the man pulls upward with a force F
whose direction makes an angle of 30.0°
with the ramp (Fig. E4.4).
(a) How large a force F is necessary for
the component F, parallel to the ramp
to be 90.0 N? (b) How large will the
component F, perpendicular to the ramp
be then?
Figure E4.4
30,0
|20.0°
Problem
In the end of the Chapter 4 Problem 4.4 of your book consider that the trunk has mass M travels at a constant velocity along a frictionless inclined and the angles involved are 0j and
8s, where 0, corresponds to the angle with respect to the direction of motion and 6j is the angle of the inclined. What are the simplified expressions for the tension on the rope and
the normal force on the trunk in terms of M, g and the angles?
Answer
T =
(8)/
n = (Mg)(
(6)
Os +
Transcribed Image Text:4.4 • A man is dragging a trunk up the loading ramp of a mover's truck. The ramp has a slope angle of 20.0°, and the man pulls upward with a force F whose direction makes an angle of 30.0° with the ramp (Fig. E4.4). (a) How large a force F is necessary for the component F, parallel to the ramp to be 90.0 N? (b) How large will the component F, perpendicular to the ramp be then? Figure E4.4 30,0 |20.0° Problem In the end of the Chapter 4 Problem 4.4 of your book consider that the trunk has mass M travels at a constant velocity along a frictionless inclined and the angles involved are 0j and 8s, where 0, corresponds to the angle with respect to the direction of motion and 6j is the angle of the inclined. What are the simplified expressions for the tension on the rope and the normal force on the trunk in terms of M, g and the angles? Answer T = (8)/ n = (Mg)( (6) Os +
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