Question
Asked Dec 4, 2019
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The diagram shows a sign that wighs 50 N hanging from a uniform horizontal pole. The pole weighs 30 Newton's and it is 1.6 m long. Determine the tension in the supporting cable C and the magnitude and direction of the two component forces at the pivot, P, exert on the pole.

 

42
P
Mom's
Diner
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42 P Mom's Diner

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Expert Answer

Step 1

The net torque about the axis is,

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[T sin(42)(.6)]-[(50)(L6)]+[(30)(0.3)] T 97 N

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Step 2

The required magnitude ...

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(Tcose+(30+50)-Tsine) (97)cos(42)(50+50)-[07)sin(42) =73.55N

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Mechanical Properties of Matter

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