Question
Asked Dec 25, 2019
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A laser beam strikes one end of a slab of material, as in
Figure P22.56. The index of refraction of the slab is 1.48. Determine
the number of internal reflections of the beam before it
emerges from the opposite end of the slab.

42.0 cm
3.10 mm
n = 1.48
30.0
Figure P22.56
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42.0 cm 3.10 mm n = 1.48 30.0 Figure P22.56

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Expert Answer

Step 1

The ray diagram of the beam is shown below.

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N = 1 N = 3 x= 3d 0.310 cm O = 50° x= 2d x= 4d x = 5d x=d N =2

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Step 2

Using Snell’s law, the refraction angle is

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sine 0, = sin slab (1)sin 50° = sin' 1.48 = 31.2°

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Step 3

Then the dista...

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3.10mm/2 d= tan 0, 3.10x10°m/2 tan 31.2° = 0.256 x 10 m

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