46. A tire manufacturer has been producing tires with an average life expectancy of 26,000 miles. Now the company is advertising that its new tires' life expectancy has increased. In order to test the legitimacy of the advertising campaign, an independent testing agency tested a sample of 6 of their tires and has provided the following data. Life Expectancy (In Thousands of Miles) 28 27 25 28 29 25 Determine the mean and the standard deviation. a. At the .01 level of significance using the critical value approach, test to determine whether or not the tire company is using legitimate advertising. Assume the population is normally b. distributed. ANSWER: a. X- 27,s = 1.67 (rounded) Ho: 4 <26 (in thousands of miles) Ha: 4 > 26 (in thousands of miles) Since t= 1.467 <3.365, do not reject Họ and conclude that there is insufficient evidence to support the manufacturer's claim. b.

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A: Given (A2): SE=10 for N=12 (A2): SE= 50, for N=25

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Q: 2) The annual salaries of employees in a large company are approximately normally distributed with a…

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A: Standard deviation of sample mean is also know as Standard error

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A: Formula : Z =(X - μ)/σ

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Q: Suppose that a large Introduction to Psychology class has taken a midterm exam, and the scores are…

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A: Answer: From the given data

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Q: 1. The average grade of 2nd year students majoring in Civil Engineering is normally distributed with…

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A:

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A: Given  μ=38, σ=9.002 and n=80

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Q: we look at a random sample of 1000 united flights in the month of December comparing the actual…

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Q: The average undergraduate cost for tuition, fees, and room and board for two-year institutions last…

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