4x+5 [x]h I+[x]h 7+[x]h E+[x]h .00104 .00130 .00162 .00200 .00244 .00295 .00113 .00144 .00180.00222 .00272 .00328 .00124 .00159 .00199 .00247 .00301 .00363 he probability that an individual currently aged 60, that was accepte = ago will die in the next 4 years?
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![3)
Use the following 5 year select table for this question.
[x]
9(x]+1
9[x]+2
9[x]+3
9[x]+4
9x+5
Attained age
57
.00104
.00130
.00162
.00200
.00244
.00295
62
58
.00113
.00144
.00180
.00222
.00272
.00328
63
59
.00124
.00159
.00199
.00247
.00301
.00363
64
What is the probability that an individual currently aged 60, that was accepted for insurance
two years ago will die in the next 4 years?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc00f8057-b676-4758-a0ff-cf4b0fd913fd%2F51d5eb9d-3f1f-46c2-9a7c-159a8a167d6d%2F1r46dc_processed.jpeg&w=3840&q=75)
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- A random sample of 80 poultry farms of one variety gave an average production of 240 eggs per bird. Another random sample of 50 poultry farms of another variety gave an average production of 195 eggs per bird. At a=0.05 is there sufficient evidence to support that there is a significant difference between the egg production of the two varieties of birds. Assume o1 =18 eggs and o2=15 eggsThe management of the local zoo wants to know if all of their animal exhibits are equally popular. If there is significant evidence that some of the exhibits are not being visited frequently enough, then changes may need to take place within the zoo. A tally of visitors is taken for each of the following animals throughout the course of a week, and the results are contained in the following table. At α=0.005, determine whether there is sufficient evidence to conclude that some exhibits are less popular than others. Animal Exhibits at the Zoo Elephants Lions/Tigers Giraffes Zebras Monkeys Birds ReptilesNumber of visitors 152 175 185 144 145 171 163 Step 2 of 4 : Calculate the expected value for the number of visitors for the birds exhibit. Enter your answer as a fraction or a decimal rounded to three decimal places. Step 3 of 4: Compute the value of the test statistic. Round any calculations to at least six decimals places and round your final answer to three…If the alleles A and B of the cystic fibrosis gene occur in a population with frequencies p and 1 - p (where pis between 0 and 1), then the frequency of heterozygous carriers (carriers with both alleles) is 2p(l - p). Which value of p gives the largest frequency of heterozygous carriers?
- An SRS of 100 flights by Speedy Airlines showed that 64 were on time. An SRS of 100 flights by Happy Airlines showed that 80 were on time. Let pS be the proportion of on-time flights for all Speedy Airline flights, and let pH be the proportion of all on-time flights for all Happy Airlines flights. Is there evidence of a difference in the on-time rate for the two airlines? To determine this, you test the hypotheses H0 : pS – pH 0, Ha : pS – pH 0. The P-value of your test is 0.0117. Which of the following is an appropriate interpretation of the P-value? a. If the on-time rates for the two airlines are equal, there is a 0.0117 probability of getting samples with a difference as far or farther from zero as these samples. b. If the on-time rates for the two airlines are not equal, the probability of getting samples with a difference as far or farther from zero as these samples is 0.9883. c. The probability of making a Type I error is 0.0117. d. The probability of making a Type II error…The management of the local zoo wants to know if all of their animal exhibits are equally popular. If there is significant evidence that some of the exhibits are not being visited frequently enough, then changes may need to take place within the zoo. A tally of visitors is taken for each of the following animals throughout the course of a week, and the results are contained in the following table. At α=0.025, determine whether there is sufficient evidence to conclude that some exhibits are less popular than others. Animal Exhibits at the Zoo Elephants Lions/Tigers Giraffes Zebras Monkeys Birds Reptiles Number of visitors 164 166 172 188 165 139 142 Copy Data Step 3 of 4 : Compute the value of the test statistic. Round any intermediate calculations to at least six decimal places, and round your final answer to three decimal places.Show that (X+1)/(n+2) is a biased estimator of the binomial parameter θ. Is this estimator asymptotically unbiased?
- The management of the local zoo wants to know if all of their animal exhibits are equally popular. If there is significant evidence that some of the exhibits are not being visited frequently enough, then changes may need to take place within the zoo. A tally of visitors is taken for each of the following animals throughout the course of a week, and the results are contained in the following table. At α=0.05, determine whether there is sufficient evidence to conclude that some exhibits are less popular than others. Animal Exhibits at the ZooElephants Lions/Tigers Giraffes Zebras Monkeys Birds ReptilesNumber of visitors 137 129 161 147 160 134 131 Step 3 of 4 : Compute the value of the test statistic. Round any intermediate calculations to at least six decimal places, and round your final answer to three decimal places. Step 4 of 4: Draw a conclusion and interpret the decision. (Reject or fail to reject, Is there enough evidence or not?)Consider a study using a between-groups design with between-groups df = 3 and within-groups df = 4. Given an F ratio of 6.8, the researcher should: a. reject the null hypothesis if alpha is .05 but fail to reject if alpha of .01 b. reject the null hypothesis if alpha is .01 but fail to reject if alpha of .05 c. reject the null for both alpha = .01 or alpha = .05 d. fail to reject the null hypothesis whether alpha is .01 or .05A certain company produces fidget spinners with ball bearings made of either plastic or metal. Under standard testing conditions, fidget spinners from this company with plastic bearings spin for an average of 2.7 minutes, while those from this company with metal bearings spin for an average of 4.2 minutes. A random sample of three fidget spinners with plastic bearings is selected from company stock, and each is spun one time under the same standard conditions; let x¯1x¯1 represent the average spinning time for these three spinners. A random sample of seven fidget spinners with metal bearings is selected from company stock, and each is likewise spun one time under standard conditions; let x¯2x¯2 represent the average spinning time for these seven spinners. What is the mean μ(x¯1−x¯2)μ(x¯1−x¯2) of the sampling distribution of the difference in sample means x¯1−x¯2x¯1−x¯2 ? 3(2.7)−7(4.2)=−21.33(2.7)−7(4.2)=−21.3 A 3−7=−43−7=−4 B 2.7−4.2=−1.52.7−4.2=−1.5 C…
- In a clinical study, a random sample of 540 participants agree to have their blood drawn, which is to be examined for the presence of antibodies against a certain contagious disease. It is found in 22% of the blood samples, which experimenters hope to extrapolate to the general population. From this random sample, 10 participants' blood samples are selected at random. If X is the number of samples out of the 10 who have these antibodies, what can we say about X? A. The sample size is not large enough for us to approximate X using a normal distribution B.The expected value of X is 22 C. X can be approximated using a normal distribution in lieu of a binomial distribution D. X has a sampling distribution that is normalIf H1: μ1 – μ0 < 0, then zobs = -1 has a lower p-value than zobs =1. True or false?Suppose now that you have good arguments to say that the association between X andC (the unobserved confounding factor, here IQ at age 3), measured by γCX, is of a similarmagnitude as the association between X and A, measured by γAX — which you can computein your data (since A is observed). Would this new condition (γCX = γAX). Why?