4xgxcoseyxDT×D4×AP128xµ×Lh= 0,53 cmQ= 72000 cm³/sD= 20 mmD= 2mm0= 45°y= 13600N/m30= .. .N/mu= 400 kN s/km2L= 1000 cmAP=..N/m2 (Pa)2xgxhxycy-1V×D9h= 76 mmRe= 121538 (boyutsuz)Yc= 0,0136 N/cm3V= 12,01 km/h9- 46,8 cm?/sV= 7,9.10-' m/sD=.... .mg= 9,81 m/s?Y=.. .kN/m³8×LxQ2xfr2×g×D5L= 5 kmf= 0,01277 (boyutsuz)g= 9,81 m/s?Q= 1440000 dm³/hD= 442,1 mmh=........m

Hello. Since you have posted multiple questions and not specified which question needs to be solved,…

Answered: 4xgxcos@yxD h= 0,53 cm D= 2mm 0= 45° Y=…

Science

Physics

4xgxcos@yxD h= 0,53 cm D= 2mm 0= 45° Y= 13600N/m³ ..N/m

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 81AP: The nearest neutron star (a collated star made primarily of neutrons) is about 3.00 1018 m away...

See similar textbooks

Related questions

Q: Solve for the missing angle and weight 40 7 slug W 110 dyne

A: Given data: The angle is θ=40° The weight is W1=110 dyne Standard values, 1 dyne=105 N 1 slug…

Q: 4cm h =0.04 y ↑ D 1.21m H12cm 0.42m

A: In this question they are asking to find the angle of the track The H is given = 12 cm = 0.12 m…

Q: The speed of light and a piece of glass of 220,376,573.55 m/s. What it's index of fraction?

Q: north; 30 mm west; 40 mm at 60° west of north; 50 mm at 30° west of south as shown in Fig (1). Solve…

A: The component resolution of the four-vector is drawn below:-

Q: A pole which leans to the sun by 10° 15’ from the vertical casts a shadow of 9.43 m on the level…

Q: 125 cm above the water leve from his foot at the edge of th spot of light hit the bottom of edge, if…

A: Given:- The height of the flashlight above the water level h = 125 cm = 1.25 m the flashlight on…

Q: What is the measurement depicted in the image ?

Q: 56.79 cm + 1.458 cm + 116 cm = _____________cm

Q: Given s0 = 7.35 cm and si = 17.0 cm find f.

Q: The speed of light in a piece of glass of 266,741,360.51 m/s. What it its index of refraction?

Q: In a certain library the first shelf is 13.0 cm off the ground, and the remaining four shelves are…

A: Given: Mass, m = 1.4 kg Average shelf holds 29 books. Height of the book = 22 cm = 22 x 10-2 m…

Q: Find the centeroid of the shaded area * ?.shown in fig y Dimensions in mm 45 -20 100

A: Consider the triangle as section 1, semi-circle as section 2, and complete circle as section 3.

Q: Solve for the missing angle and weight 40 7 slug 110 dyne

A: Tension in the left rope attached to 7 slug = T = 110 dyne = 00011 N Tension in the right rope…

Q: h 1,- 2; = A2 = "-(1- cos0) M.C %3D

A: To derive compton equationλf - λi = ∆λ = hmec(1-cosθ)

Q: convert 89cm^2 to m^2

A: Given that As we know that cm2 is the unit of Area. Let A be the area,…

Q: toomm x 30

A: Given parameters, length of the tank, l = 400 mm = 0.4m breadth of the tank, b =…

Q: 30 mm 60 mm 90 mm 30 mm 20 mm

A: In a given figure we calculate first moment area about y axis

Q: A spherical mirror has a center of curvature that is 21.3 cm from the mirror. If the magnification…

Q: 500 cm/50 cm = 10cm What's wrong with this?

A: Given calculation is: 500 cm/50 cm =10 cm The calculation part of the given solution is correct but…

Q: 3 žIn(k) + žIn(2mm) – 31

Q: If light travelling through air enters oil at an angle of 36.1° and the speed of light in the oil is…

A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: For the distance D=5.5cm and radius = 1.75cm ,the numerical aperture is a. 0.287 b. 0.268 c. 0.303…

Q: B= 25 15° A = 20 45° 30 C= 30

Q: Instructions 50 cm 10 cm 8.0 A R = 1.0 x 10-3

A: According to Faraday law Induced emf is the rate of change of magnetic flux. Induced current=…

Q: cm б 1234 5678910

A: It is the standard caliper, so the least count of the caliper is 0.01 cm.

Q: A = 400 ft TB = 390 ft В

Q: 60 mm , 60 mm В AR=75 mm 105 mm 100 N

A: Let F be the force at point A.

Q: TH = 6,400, 000m. %3D

Q: In a Newton’s ring experiment, the diameter of the 5th ring is 0.30cm and diameter of the15th ring…

A: Given data: The given problem is based on Newton's ring. The diameter of the 5th ring is, d5 = 0.30…

Q: А (A- 44.0) 28.0° 56.0% В (В 3D 26.5)

Q: a. 2 cm 1 cm 5 cm (Enet)z (Ener)y

Q: The percent reflectivity of a surface is known as its __________. Group of answer choices a.…

A: Albedo Option c.

Q: F=1.5N Scale 3cm=1N What the value of F in cm?

A: Given: Force (F) = 1.5 N The scale : 1 N = 3 cm

Q: What is the measurement depicted in the image?

A: Measurement in vernier callipers = main scale reading + vernier scale reading × least count

Q: L2 L, = 10 cm A, = 6 sq.cm L2= 25 cm A = 4 sq.cm %3D

Q: arsighted person whose far p + 60 cm -30 сm + 30 сm

A: The solution can be given as follows :-

Q: F1 = 5N at 25 (degree) F2 = 4N at 112 (degree) Find FR and direction. Draw the FBD. Scale: 1 cm =…

Q: 100 mm Parallel to z axis 100 mm 45° 100 mm 75 mm

A: we have to find centroid in above question, so the solution of the question in below step.

Q: pls give a explanation for that

Q: Find H (in cm) if x=20 cm, h=35 cm and L = 3.2 m. н

A: Given: x = 20 cm h = 35 cm L = 3.2 m = 320 cm

Q: + 4x = 0 dt? %3D

A: Equation of motion along Ox after time t is d2xdt2 +4x = 0 which is second order harmonic equation

Q: a. 2 cm 42 1 cm 5 cm (Ene)y":

A: Electric field due to positive charge is radially outwards and due to negative is inwards

Q: A fountain of water is located at the center of a circular pool. Not wishing to get his feet wet, a…

Q: F=1.7N Scale 3cm = 1N What the value of F in cm?

A: Given: The value of force F = 1.7 N The scale 1 N = 3 cm

Q: In spherical polar coordinates (l, q, a), q denotesthe polar angle around z-axis and a denotes the…

A: The cartesian coordinate can be written as follow: x=rsinq.cosa y=rsinqsina z=rsinq

Q: The speed of light in vacuum is 2.990x10^8 m/s. What is the speed of light in Km/h

Question

4xgxcoseyxD
T×D4×AP128xµ×L
h= 0,53 cm
Q= 72000 cm³/s
D= 20 mm
D= 2mm
0= 45°
y= 13600N/m3
0= .. .N/m
u= 400 kN s/km2
L= 1000 cm
AP=.
.N/m2 (Pa)
2xgxhxycy-1
V×D9
h= 76 mm
Re= 121538 (boyutsuz)
Yc= 0,0136 N/cm3
V= 12,01 km/h
9- 46,8 cm?/s
V= 7,9.10-' m/s
D=.... .m
g= 9,81 m/s?
Y=.. .kN/m³
8×LxQ2xfr2×g×D5
L= 5 km
f= 0,01277 (boyutsuz)
g= 9,81 m/s?
Q= 1440000 dm³/h
D= 442,1 mm
h=........m

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Ā = 3.0N,150%, what is the y component
The nearest neutron star (a collated star made primarily of neutrons) is about 3.00 1018 m away from Earth. Given that the Milky Way galaxy (Fig. P1.81) is roughly a disk of diameter 1021 m and thickness 1019 m, estimate the number of neutron stars in the Milky Way to the nearest order of magnitude. Figure P1.81
2506025 J seems like a bit of a big number how is this possible?
A star’s spectrum emits more radiation with a wavelength of 690.0 nm than with any other wavelength. If the star is 9.78 ly from Earth and its radius is 7.20 × 108 m, what will an Earth-based observer measure for this star’s intensity? Stars are nearly perfect blackbodies. (Note: ly stands for light-years.) Answer in W/m2
The fictional rocket ship Adventure is measured to be 50 mlong by the ship’s captain inside the rocket. When the rocketmoves past a space dock at 0.5c, space-dock personnelmeasure the rocket ship to be 43.3 m long. What is itsproper length?(a) 50 m. (b) 43.3 m. (c) 93.3 m. (d) 13.3 m
Una partícula parte de origen en t = 0 con una velocidad de 6.0i m / s y se mueve en el plano xy con una aceleración constante de (–2.0i + 4.0j) m / s2. En el instante en que la partícula alcanza su máxima componente en x positiva, ¿qué tan lejos está del origen?
What is the uncertainty in the temperature difference, ΔT, between the two temperature T1 = (25.0 ± 0.5) oC and T2 = (30.0 ± 0.3) oC?
Implications of uncertainty(a) What is the uncertainty of our triple beam balance?i. ±0.1 gii. ±0.02 g (20% of least count) - correct answeriii. ±1 giv. My measurements are perfect, I don’t have uncertainties (b) Based on your previous answer, which measurement(s) have the proper significantfigures for our triple beam balance?i. 17.32 gii. 1.9 giii. 0.67 giv. 123.45 gv. 0.12345 kgvi. 111.1 gvii. 10.00 g (c) Explain how the uncertainty associated with the measurement apparatus determined the accuracy (appropriate number of decimal places) that you should include in the measurement
Given 122 + 16y = 19y – 235, solve the equation, y =? please help me with explanation to practice with calculator.
In the LHC, protons are accelerated to a total energy of 7.80 TeV. The mass of proton is 1.673 × 10−27 kg and Planck’s constant is 6.626 × 10−34 J·s. In the reference frame of the protons, how long does it take the protons to go around the tunnel once? I know the answer is 10.8ns. The solutions posted on here, do not come within 1% of that answer so I cannot trust that the steps are correct. Please give step by step instructions on how to arrive at 10.8 ns
(a) Estimate the mass of the luminous matter in the known universe, given there are 1011 galaxies, each containing 1011 stars of average mass 1.5 times that of our Sun. (b) How many protons (the most abundant nuclide) are there in this mates? (c) Estimate the total number of particles in the observable universe by multiplying the answer to (b) by two, since there is an electron for each proton, and then by 109, since there are far more particles (such as photons and neutrinos) in space than in luminous matter.
The "classical" radius of a neutron is about 0.81 fm (1 femtometer = 10-15 m). The mass of a neutron is 1.675×10-27 kg. a) Assuming the neutron is spherical, calculate its density in kilograms per cubic meter. b) What would be the magnitude of the acceleration due to gravity, in meters per second squared, at the surface of a sphere of radius R = 1.2 m with this same density? Recall that the gravitational constant is G = 6.67 × 10-11 m3/kg/s2.